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arlik [135]
2 years ago
6

HELP PLEASEQuestion is in the photo.I need both Part A and Part B.

Mathematics
1 answer:
posledela2 years ago
3 0

The range of f is the set of all real numbers and the range of f would not change if the value of n is changed

<h3>The range of f when n = 5</h3>

The function is given as:

f(x) =\left \{ {{x - 1;\ \ x < n} \atop {- x + 4;\ \ x \ge n}} \right.

When n = 5, we have:

The domain of the function is:

x < 5 and x ≥ 5

This means that the domain is the set of all real numbers.

The function is a linear piece wise function, and the range of a linear function is the set of all real numbers.

Hence, the range of f is the set of all real numbers.

<h3>Does changing the value of n change the range?</h3>

As stated in (a) the range of a linear function is the set of all real numbers.

This means that irrespective of the value of n; the range would remain the same

Hence, the range of f would not change if the value of n is changed

Read more about piecewise functions at:

brainly.com/question/18859540

#SPJ1

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2. I earned $9. I bought 4 candy bars for $0.85 each. How much money do I
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Answer:

A

Step-by-step explanation:

4 x $0.85= $3.40  

$9-$3.40= $5.60

5 0
3 years ago
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Emily made 75% of the baskets that she attempted if she may nine baskets how many attempts did you make?
Aneli [31]
Set up a proportion

75/100= 9 baskets/ x attempts

The ratio of numerator to denominator should be 75/100 which simplifies to 3/4. 3/4= 9/x
3*3=9, 4*3=12

x=12

Final answer: 12 attempts
8 0
3 years ago
Jack earns $50 for washing cars on the weekend. He makes an average of $4.25 in tips per hour. Write the function of Joe's earni
Elena-2011 [213]
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4 0
4 years ago
In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.
Hitman42 [59]

\longmapstoThe value of "x" is 5.

\large\underline{\sf{Solution-}}

Given that,

A trapezium ABCD in which AB || CD such that

  • AO = x - 1

  • CO = BO = x + 1

  • OD = x + 4

Now,

\rm In \: \triangle  \: AOB  \: and \: \triangle \:  COD

\rm  \: \angle  \: AOB  \: and \: \angle \:  COD \:  \:  \{vertically \: opposite \: angles \}

\rm  \: \angle  \:ABO  \: and \: \angle \:  CDO \:  \:  \{alternate \: interior \: angles \}

\bf \: \triangle  \: AOB \:  \sim \:  \triangle  \: COD \:  \:  \:  \{AA \: similarity \}

\bf\longmapsto\:\dfrac{AO}{CO}  = \dfrac{BO}{DO}

\rm \longmapsto\:\dfrac{x - 1}{x + 1}  = \dfrac{x + 1}{x + 4}

\rm \longmapsto\:(x - 1)(x + 4) =  {(x + 1)}^{2}

\rm \longmapsto\: {x}^{2} - x + 4x - 4 =  {x}^{2} + 1 + 2x

\rm \longmapsto\: 3x - 4 =  1 + 2x

\rm \longmapsto\: 3x  -  2x=  1 +4

\bf\longmapsto \:x = 5

7 0
3 years ago
If the graph of a line goes from the upper left corner of the graph to the lower right corner, what can you say about its slope?
musickatia [10]

Answer:

I believe the answer is D. Hope this helps

Step-by-step explanation:

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