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arlik [135]
2 years ago
6

HELP PLEASEQuestion is in the photo.I need both Part A and Part B.

Mathematics
1 answer:
posledela2 years ago
3 0

The range of f is the set of all real numbers and the range of f would not change if the value of n is changed

<h3>The range of f when n = 5</h3>

The function is given as:

f(x) =\left \{ {{x - 1;\ \ x < n} \atop {- x + 4;\ \ x \ge n}} \right.

When n = 5, we have:

The domain of the function is:

x < 5 and x ≥ 5

This means that the domain is the set of all real numbers.

The function is a linear piece wise function, and the range of a linear function is the set of all real numbers.

Hence, the range of f is the set of all real numbers.

<h3>Does changing the value of n change the range?</h3>

As stated in (a) the range of a linear function is the set of all real numbers.

This means that irrespective of the value of n; the range would remain the same

Hence, the range of f would not change if the value of n is changed

Read more about piecewise functions at:

brainly.com/question/18859540

#SPJ1

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Write an equation of the parabola in vertex form that passes through (0, -24) and has vertex (-6,-12)
stich3 [128]

Answer:

f(x)=-2(x+6)-12

Step-by-step explanation:

so the easiest one to do would be vertex form

f(x)=a(x-h)+k

so your vertex represents (h, k)

so plug in those values

f(x)=a(x- - 6) -12

now use the other point to solve for a

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WARRIOR [948]

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~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-7}~,~\stackrel{y_2}{7}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ -7 -2}{2}~~~ ,~~~ \cfrac{ 7 + 9}{2} \right)\implies \left( \cfrac{-9}{2}~~,~~\cfrac{16}{2} \right)\implies \left( -4\frac{1}{2}~~,~~8 \right)

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3 years ago
For a saturday matinee, adult tickets cost $5.50 and kids under 12 pay only $4.00. if 60 tickets are sold for a total of $285. h
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Which equation represents a parabola that opens upward has a minimum at x=3 and has a line of symmetry at x=3
umka2103 [35]

Answer:

y=x^2-6x+5

Step-by-step explanation:

Let us consider the equation y=x^2-6x+5

For a quadratic equation in a standard form, y=ax^2+bx+c, the axis of symmetry is the vertical line x = \frac{-b}{2a}.

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Putting the values we get,

x = \frac{-(-6)}{2\times 1} = \frac{6}{2} =3

We can see that the axis of symmetry is x=3 and the graph is giving minimum at x=3.

Therefore, the required equation is y=x^2-6x+5. Refer the image attached.


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