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Komok [63]
3 years ago
15

Solve the following equation: 2(4^2 + 10) =

Mathematics
2 answers:
Savatey [412]3 years ago
8 0

Answer:

Step-by-step explanation:

2(4^2 + 10) = 2( (4×4) + 10)

= 2(16 + 10)

= 2(26)

= 52

lesantik [10]3 years ago
3 0

Answer:

52

Step-by-step explanation:

2(4^2 + 10) =

We do what's in the parenthesis first.

4^2 = 16 and 16+10 =26.

2(26)

= 52

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A bowl of buttons contains 10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL]
kondaur [170]

Answer:

a) Probability of picking Two MAGA buttons without replacement = 0.15

b) Probability of picking a MAGA and GND button in that order = 0.0833

Probability of picking a MAGA and GND button in with the order unimportant = 0.167

Step-by-step explanation:

10 MAGA [MAKE AMERICA GREAT AGAIN] buttons, 5 GND [GREEN NEW DEAL] buttons and 10 NAW [NEVER A WALL] buttons.

Total number of buttons = 10 + 5 + 10 = 25

Let probability of picking a MAGA button be P(M) = 10/25 = 0.4

Probability of picking a GND button be P(G) = 5/25 = 0.2

Probability of picking a NAW button be P(N) = 10/25 = 0.4

a) Probability of picking Two MAGA buttons without replacement = (10/25) × (9/24) = 3/20 = 0.15

b) Probability of picking a MAGA and GND button in that order = (10/25) × (5/24) = 1/12 = 0.0833

Probability of picking a MAGA and GND button in with the order unimportant = [(10/25) × (5/24)] + [(5/25) × (10/24)] = 1/6 = 0.167

3 0
3 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

8 0
3 years ago
Is 40 a multiple of 8
Natasha2012 [34]
Yes because,
8×1 = 8
8×2 = 16
8×3 = 24
8×4 = 32
8×5 = 40

So 40 is a multiple of 8
4 0
3 years ago
A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?
kati45 [8]

Answer:

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

8 0
3 years ago
A kite flying in the air has a 12 line attached to it. Its line is pulled taut and casts a 9 shadow. Find the height of the kite
alexira [117]

Answer:

8 (7.94)

Step-by-step explanation:

You can think of it as a geometry problem.

What is formed here is a triangle, which sides ate: the line, the line's shadow, and the height from the ground to the kite (here I attach a drawing).

What you need to find is the height. We will call it H.

As the triangle formed is a right one, we can use Pitágoras' theorem. The height H squared plus the squared of the shadow is equal to the squared of the line (the hypotenuse). This is:

H^2 + 9^2 = 12^2

H^2 + 81= 144

H^2 = 63

Applying squared root in both sides

H = √63

H = 7,94

So, the height is approximately 8.

4 0
3 years ago
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