Answer:
I18 - xI such that x < 18.
ok, first let's what happens if x = 18:
I18 - xI = I18 - 18I = 0
So, at the moment we have the condition:
I18 - xI > 0.
now, if x is a really large negative number, suppose, x = -100
I18 + 100I = I118I = 118
So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:
I18 - xI > 0.
This means that the domain is:
D = (-∞, 18)
and the range is:
R = (0, ∞)
Answer:
see below
Step-by-step explanation:
DB = 9 units (by counting)
BA = 12 units (by counting)
DA can be found by using the pythagorean theorem
a^2 +b^2 = c^2
BD^2 + BA^2 = DA ^2
9^2 +12^2 = DA^2
81 +144 = DA^2
225 = DA ^2
Take the square root of each side
sqrt(225) = sqrt(DA^2)
15 = DA
LJ = 3 units (by counting)
JK = 4 units (by counting)
LK can be found by using the pythagorean theorem
a^2 +b^2 = c^2
LJ^2 + JK^2 = LK ^2
3^2 +4^2 = LK^2
9 +116 = LK^2
25 = LK ^2
Take the square root of each side
sqrt(25) = sqrt(LK^2)
5 = LK
Scale factor from BAD to JKL
15 to 5
Divide each side by 5
3 to 1
We multiply by 1/3 to go from the big to small
Answer:
The. Answer. C
Step-by-step explanation:
Answer:
6u^3
Step-by-step explanation:
