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2 years ago

Inventory was taken on Day 1, Day 2, Day 5, Day 6, and Day 7. Norris wants to know roughly what the inventory was on Day 3.

Mathematics

2 answers:

Zina [86]2 years ago

6 0

Answer:

Step-by-step explanation:

guessing

Dvinal [7]2 years ago

3 0

He should evaluate the function f(x)=−1/3 x+4 for x=3 , Option D is the correct answer.

<h3>What in Interpolation ?</h3>

Interpolation is when the line of best fit is used to determine the value of a point that is within the range of plotted points.

It is given to find the value at Day 3 which lies in the range of the points used for plotting

The line for best fit is

f(x) = (-1/3)x +4

At x = 3

f(3) = (-1/3) * 3 +4

f(3) = -1+4 = 3

Therefore He should evaluate the function f(x)=−1/3 x+4 for x=3

Option D is the correct answer.

To know more about Interpolation

brainly.com/question/18768845

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Can somebody answer this (on the picture) algebra question please

zheka24 [161]

I am torn between B and D because increased means add, but I am going to go with B 1 - 3n. I choose B because in the D option it decreases not increases.

So the answer is B.) 1 - 3n
Hope this helps! - Alyssa

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3 years ago

Velida took out a 5/1 variable-rate mortgage for $150,000. The interest rate

Afina-wow [57]

Answer:

Step-by-step explanation:

The amortization period in months is:

30 years * 12 = 360 months

The monthly interest rate would be 5.25%/12 = 0.004375

The payment for monthly mortgage formula would be:

$E=\frac{C*r}{1-(1+r)^{-n}}$

Where

E is the monthly mortgage payment

C is the cost of mortgage, cost is $150,000

r is the monthly rate of interest, which is 0.004375

n is the period, in months, which is 360

Substituting, we get our answer:

$E=\frac{C*r}{1-(1+r)^{-n}}\\E=\frac{150,000*0.004375}{1-(1+0.004375)^{-360}}\\E=\frac{656.25}{1-(1.004375)^{-360}}\\E=\frac{656.25}{0.7923}\\E=828.31$

So, the correct answer is B

3 0

3 years ago

Find the square root by factor 21904

mihalych1998 [28]

$21904|2\\10952|2\\.\ 5476|2\\.\ 2738|2\\.\ 1369|37\\.\ \ \ \ 37|37\\.\ \ \ \ \ \ 1|\\\\21904=2\times2\times2\times2\times37\times37=2^4\times37^2\\\\\sqrt{21904}=\sqrt{2^4\times37^2}=\sqrt{2^4}\times\sqrt{37^2}=2^2\times37=4\times37=148$

$\sqrt{21904}=\sqrt{4\times5476}=2\sqrt{4\times1369}=2\times2\sqrt37\times37}=4\times37=148$