All categories

3 years ago

What is, ¹⁵⁄₁ times ⁹⁄₁

Mathematics

2 answers:

torisob [31]3 years ago

5 0

The answer is 135/1, or 135 as a whole.

uranmaximum [27]3 years ago

3 0

Answer:

135

Step-by-step explanation:

happy to help!~~

You might be interested in

From 42 to 72 find each percent round to the nearest percent

neonofarm [45]

Change/original * 100
(72-42)/42 * 100
30/42 * 100 = .7143 *71.43 100 = 71%

6 0

3 years ago

Read 2 more answers

Twice one number added to another umber is 18. If the second number is equal o 12 less than 4 times the first number, find the t

cestrela7 [59]

The answer is 12 and 6 because twice the number which is 6 is 12

4 0

3 years ago

Use the identity below to complete the tasks:

quester [9]

Answer:

$a=[2q^{2}r]$

$b=[3s^{2}t]$

Step-by-step explanation:

we have

$8q^{6}r^{3}+27s^{6}t^{3}$

we know that

$8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}$

$27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}$

therefore

$a=[2q^{2}r]$

$b=[3s^{2}t]$

substitute

$a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})$

$[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])$

7 0

3 years ago

Read 2 more answers

If 3x = 21, find the value of 23 - 4x

quester [9]

Answer:

- 5

Step-by-step explanation:

Given

3x = 21 ( divide both sides by 3 )

x = 7

Then

23 - 4x = 23 - 4(7) = 23 - 28 = - 5

7 0

3 years ago

Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a

Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .