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Trava [24]
3 years ago
14

Jessie brought 3 t shirts for $6 each. And 4 t shirts for $5 each. What expression can you use to describe what Jessie bought?

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0

Answer: 18+20

Step-by-step explanation:

kotegsom [21]3 years ago
6 0

Answer:

(3 x 6) + (4 x 5)

This is the expression!

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How many angle measurements do you need to figure out the measurements of all the labeled angles in the figure below?
liq [111]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 18% each week. The following function represents
8090 [49]

Answer:

f(z) = 86.(0.169)z

Step-by-step explanation:

Let's call

  • x = number of weeks
  • z = number of days

We have the growing function f(x) = 86.(1.18)x. If we want to write f in terms of z, we need to consider that x = z/7, since there are 7 days in each week. Then,

86.(1.18)x = 86.(1.18)z/7 = 86.(0.169)z

f(z) = 86.(0.169)z

6 0
3 years ago
CAN SOMEONE PLEASE HELP ME PLEASE PLLEASE THANKS!!
Anestetic [448]
I believe you could find the information in an A) Almanac 

~Hope This Helped~


5 0
3 years ago
Suppose that a sample of size 100 is to be drawn from a population with standard deviation 10.
larisa86 [58]

Answer:

a) 68% probability that the sample mean will be within 1 of the value of μ.

b)

1)

Approximately 95% of the time, x will be within 2 of μ.

2)

Approximately 0.3% of the time, x will be farther than 3 from μ.

The last:

n = 40

n = 65

n = 130

n = 520

Step-by-step explanation:

To solve this problem, it is important to know two concepts: The Empirical Rule and the Central Limit Theorem.

Empirical Rule

The Empericial Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measuers are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size, of at least 30, can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Suppose that a sample of size 100 is to be drawn from a population with standard deviation 10.

So \sigma = 10, n = 100, s = \frac{10}{\sqrt{100}} = 1

(a) What is the probability that the sample mean will be within 1 of the value of μ?

Within 1 is within one standard deviation of the mean \mu.

So there is a 68% probability that the sample mean will be within 1 of the value of μ.

(b) For this example (n = 100, σ = 10), complete each of the following statements by computing the appropriate value. (Round the answers to the nearest whole number.)

(1) Approximately 95% of the time, x will be within___ of μ.

By the empirical rule, 95% of the measures are within 2 standard deviations of the mean. In our sample, the standard deviation is 1.

So

Approximately 95% of the time, x will be within 2 of μ.

(2) Approximately 0.3% of the time, x will be farther than___ from μ.

By the empirical rule, 99.7% of the measures are within 3 standard deviations of the mean. In the other 0.3% of the time, the measures are farther than 3 standard deviations of the mean. In our sample, the standard deviation is 1.

So:

Approximately 0.3% of the time, x will be farther than 3 from μ.

A random sample is selected from a population with mean μ = 100 and standard deviation σ = 10. For which of the sample sizes would it be reasonable to think that the xsampling distribution is approximately normal in shape? (Select all that apply.)

As we saw above, in the central Limit theorem, we should use a sample size of at least 30. So

n = 40

n = 65

n = 130

n = 520

7 0
3 years ago
Which of the following is a factor in the algebraic expression: p(4-p^3) + q?
Brilliant_brown [7]

Answer:

A. 4-p^3

Step-by-step explanation:

p(4-p^3) + q

factors: p and (4-p^3)

so answer:

A. 4-p^3

8 0
3 years ago
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