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Readme [11.4K]
2 years ago
7

Find the least common denominator for these

Mathematics
1 answer:
Roman55 [17]2 years ago
6 0

The common denominator is 3a²

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What is the distance between C(-1,5) and D17, 20)<br> I need the answer
Tcecarenko [31]

Answer:

the distance is 23.43 u

Step-by-step explanation:

See the picture below, please

5 0
3 years ago
Sarah, Fiona and David share £40 in a ratio 3:3:2. How much money does each person get?
LuckyWell [14K]

Answer:

ratio:3:3:2

total of ratio=3+3+2=8

total money=40

sara gets 5x 3/8=15

eiona gets 5x 3/8+15

david gets=5x 2/8=10

Step-by-step explanation:

5 0
3 years ago
Jacob is going on a road trip across the country. He covers 10 miles in 15 minutes. He then spends 10 minutes buying gas and som
baherus [9]

Answer:

The distance traveled between 10 minutes and 15 minutes is increasing.

Step-by-step explanation:

Jacob is going on a road trip across the country. He covers 10 miles in 15 minutes.

Therefore, between the 10 minutes and 15 minutes, Jacob was in motion and if he covers 10 miles in 15 minutes with a constant speed, then Jacob will cover \frac{10}{15} \times (15 - 10) =  3.33 miles in that period.

So, the distance traveled between 10 minutes and 15 minutes is increasing.

(Answer)

6 0
3 years ago
Read 2 more answers
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
What is the volume of the rectangular prism?
lara31 [8.8K]
1/2^3=1/8
we have 30 of them so
30.1/8=30/8 => 3 and 6/8 or 3 and 3/4 if simplified
6 0
2 years ago
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