Given f(x) = 17-X^2,
what is the average rate of change in f(x) over the interval [1, 5]?
1 answer:
Answer:6
Step-by-step explanation:
Rate of change- differentiate the equation
f’(x)= 2x
Average over interval [1,5] - Find rate of change when x=1 and when x=5. Add them and divide by 2
F’(1)=2(1)
F’(1)=2
F’(5)=2(5)
F’(5)=10
Avg. =(2+10)/2
=12/2
=6
You might be interested in
2x + 3y = 18
3y = 18 -2x
y = (18/3) - (2/3)x
y = 6 - 2/3x
y =-2/3x + 6
Answer:
Factor a2 - 11a + 30
A) (6 - a)(5 - a)
B) (a + 2)(a + 15)
<h2><u><em>
C) (a + 6)(a + 5) <=YOUR ANSWER</em></u></h2>
D) (a - 6)(a -5)
Answer:
#1- 20.25 kg of milk
#2- 80kg of butter
Step-by-step explanation:
If it’s referring to 137 out of 1700, divide 137 by 1700 and multiply by 100. same for the other, except you divide 137 by 390.
check the picture below.
notice, both pairs of opposite sides are parallel.