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RSB [31]
3 years ago
5

Given f(x) = 17-X^2, what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:6

Step-by-step explanation:

Rate of change- differentiate the equation

f’(x)= 2x

Average over interval [1,5] - Find rate of change when x=1 and when x=5. Add them and divide by 2

F’(1)=2(1)

F’(1)=2

F’(5)=2(5)

F’(5)=10

Avg. =(2+10)/2

=12/2

=6

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<img src="https://tex.z-dn.net/?f=f%20%3D%28x%29%20%3D%20%5Cfrac%7Bx%7D%7B4%7D%20" id="TexFormula1" title="f =(x) = \frac{x}{4}
Inga [223]

Answer:

g(x) = \frac{x+3}{x-3}

Step-by-step explanation:

From the picture attached,

Given function is,

f(x) = x + 1

We have to find the value of g(x) if the composite function has been given as,

f[g(x)] = g(x) + 1 = \frac{2x}{(x-3)}

g(x) = \frac{2x}{(x-3)}-1

      = \frac{2x-(x-3)}{(x-3)}

      = \frac{(x+3)}{(x-3)}

Therefore, g(x) = \frac{x+3}{x-3} will be the answer.

5 0
3 years ago
Help I need the answers
jolli1 [7]
240
/ \
5 48
/ \
6 8
/ \ / \
3 2 4 2
7 0
4 years ago
Read 2 more answers
A business school has a goal that the average number of years of work experience of its MBA applicants is more than three years.
gizmo_the_mogwai [7]

Answer:

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

p_v =P(z>0.280)=0.390  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=3.1 represent the sample mean

\sigma=\sqrt{6} represent the sample standard deviation for the sample

n=47 sample size  

\mu_o =3 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 3, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3  

Alternative hypothesis:\mu > 3  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.1-3}{\frac{2.449}{\sqrt{47}}}=0.280    

P-value

Since is a one side test the p value would be:  

p_v =P(z>0.280)=0.390  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its NOT significant higher than 0.3 at 1% of signficance.  

3 0
3 years ago
Tickets to a hockey game cost $45. You and 3 of your friends decide to go together. how much will your tickets cost all together
MAXImum [283]

Answer:

135

Step-by-step explanation:

Well 3 friends and 45 dollars each

45*3=135

3 0
3 years ago
Read 2 more answers
Please answer (-4) + (-5)
sertanlavr [38]
-9

There are the same signs so you'd just add them together and use whatever sign they are..
7 0
3 years ago
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