Given f(x) = 17-X^2,
what is the average rate of change in f(x) over the interval [1, 5]?
1 answer:
Answer:6
Step-by-step explanation:
Rate of change- differentiate the equation
f’(x)= 2x
Average over interval [1,5] - Find rate of change when x=1 and when x=5. Add them and divide by 2
F’(1)=2(1)
F’(1)=2
F’(5)=2(5)
F’(5)=10
Avg. =(2+10)/2
=12/2
=6
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if my answer helps please mark as brainliest.
<span>the rate of decay each month can calculated using the following formula: </span><span> 6%/year × 1 year/(12 months) = 0.5%/month 0.06 x 1/12 = 0.005/month </span><span>So the 0.5% is the right answer. I hope it helped.</span>
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Step-by-step explanation:
Simplify the terms.
8a+3+5a-2a
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