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2 years ago

What is i really need help

Mathematics

1 answer:

notsponge [240]2 years ago

3 0

Answer: cccc

Step-by-step explanation: dum c

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Consider the function f(x)=9-x^2/x^2-4 For which intervals is f(x) positive? Check ALL that apply.

solong [7]

Answer:

a. f (x) < 0 for x ∈ (-∞ ,-3)

b. f (x) > 0 for x ∈ (-3,-2)

c. f (x) < 0 for x ∈ (-2,2)

d. f (x) > 0 for x ∈ (2,3)

e.f (x) < 0 for x ∈ (3,∞)

Step-by-step explanation:

Here, the given function is: $f(x)= \frac{9-x^2}{x^2-4}$

Now, to check for the sign of f(x) at x = k, put the value of x from the given interval.

We get:

<u>a. (-infinity, -3) </u>

put k = -4 from the given interval

We get $f(-4)= \frac{9-(-4)^2}{(-4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (-∞ ,-3)

b. (-3, -2)

put k = -2.5 from the given interval

We get $f(-2.5)= \frac{9-(-2.5)^2}{(-2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (-3,-2)

c. (-2, 2)

put k = 0 from the given interval

We get $f(0)= \frac{9-(0)^2}{(0)^2-4} = \frac{9}{-4} = -\frac{9}{4} < 0$

⇒ f (x) < 0 for x ∈ (-2,2)

d. (2, 3)

put k =2.5 from the given interval

We get $f(2.5)= \frac{9-(2.5)^2}{(2.5)^2-4} = \frac{9-6.25}{6.25-4} = \frac{2.75}{2.25} > 0$

⇒ f (x) > 0 for x ∈ (2,3)

e. (infinity, 3)

put k = 4 from the given interval

We get $f(4)= \frac{9-(4)^2}{(4)^2-4} = \frac{9-16}{16-4} = \frac{-7}{12}$

⇒ f (x) < 0 for x ∈ (3,∞)

7 0

4 years ago

Which one a b c or d

sp2606 [1]

C it’s Just look it up bro

6 0

3 years ago

What is the vertex form, f(x) = a(x − h)2 + k, for a parabola that passes through the point (4, −3) and has (5, 2) as its vertex

VARVARA [1.3K]

Given that the vertex (h, k) is (5, 2), you know the vertex form will look like
f(x) = a(x -5)² +2
for some value of "a" that makes f(4) = -3. That value of "a" can be found by substituting the given values in the above equation for f(x) and solving for "a".
-3 = a(4 -5)² +2
-3 -2 = a×1²
a = -5

This means the appropriate choice is ...
C) Vertex form: f(x) = -5(x -5)² +2; Standard form: -5x² +50x -123

7 0

3 years ago

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HELP FASTTTT<br> explain how to determine the end behavior of a polynomial

Crazy boy [7]

Answer:

Step-by-step explanation:

Given : Statement.

To find : explain how to determine the end behavior of a polynomial.

Explanation :

End behavior of the polynomial is depending on the leading coefficient and the degree of the polynomial.

If the leading coefficient is positive and degree is even then the both end will be up .

If the leading coefficient is negative and degree is even then the both end will be down .

If the leading coefficient is positive and degree is odd then the right end will be up and left end will be down .

If the leading coefficient is negative and degree is odd then the right end will be down and left end will be up .

5 0

3 years ago

Read 2 more answers

Help quickly please hurry i am almost done

Fittoniya [83]

Answer:

Might be wrong but i got c( NOPE NOT C ITS A

Step-by-step explanation:

4 0

3 years ago