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Mathematics

2 answers:

Schach [20]4 years ago

6 0

Answer:

Step-by-step explanation:

-15<-9 and |-9|<|-15|

small negative numbers like -1, -2 are actually considered bigger than larger negative numbers like -15, -16.

kondor19780726 [428]4 years ago

4 0

Answer:

The third option.

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Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.

Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

$\triangle ABC$ and $\triangle DEC$ .

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and $\angle B$ and $\angle E$ are alternate angles $\Rightarrow$ $\angle B = \angle E$ .

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

$\Rightarrow \angle ACB = \angle DCE$

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. $\angle B = \angle E$

2. EC = CB

3. $\angle ACB = \angle DCE$

So, we can in see that in $\triangle ABC$ and $\triangle DEC$ , two angles are equal and side between them is also equal to each other.

Hence, proved that $\triangle ABC$ $\cong$ $\triangle DEC$ .

8 0

3 years ago

What is common fraction?

Orlov [11]

a fraction (such as ¹/₂ or ³/₄) in which the numerator and denominator are both integers and are separated by a horizontal or slanted line — compare decimal fraction.