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3 years ago

HELP FASTTTT explain how to determine the end behavior of a polynomial

Mathematics

2 answers:

tatiyna3 years ago

8 0

Answer:

To determine the end behavior of a polynomial, graph it and look at the ends of the line. The ends include which direction the polynomial is facing upwards/downwards, and leftwards/rightwards. The degree will and leading coefficient play a role in this too. Refer to the Law of Signs.

Step-by-step explanation:

Crazy boy [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Given : Statement.

To find : explain how to determine the end behavior of a polynomial.

Explanation :

End behavior of the polynomial is depending on the leading coefficient and the degree of the polynomial.

If the leading coefficient is positive and degree is even then the both end will be up .

If the leading coefficient is negative and degree is even then the both end will be down .

If the leading coefficient is positive and degree is odd then the right end will be up and left end will be down .

If the leading coefficient is negative and degree is odd then the right end will be down and left end will be up .

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3 years ago

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2 years ago

Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
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$12=-12$
Answer:
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3 years ago

Write an equation for the line perpendicular to the line y= -2/3+7 which passes through the point (-5,6)

zysi [14]

Y = -2/3x + 7.....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. All tht means is take the original slope, flip it, and change the sign. So we take -2/3....flip it making it -3/2.....change the sign making it 3/2. So ur perpendicular line will have a slope of 3/2.

y = mx + b
slope(m) = 3/2
(-5,6)....x = -5 and y = 6
now sub and find b, the y int
6 = 3/2(-5) + b
6 = -15/2 + b
6 + 15/2 = b
12/2 + 15/2 = b
27/2 = b
so ur perpendicular equation is : y = 3/2x + 27/2 <==

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3 years ago