Answer:
A = 981.3 ft^2
Step-by-step explanation:
Here we're calculating the area of a semicircle of radius 25 ft.
The area of a circle is A = (pi)(r)^2, and that of a semicircle of the same radius is A = (1/2)(pi)(r)^2.
Here pi = 3.14 and r = 25 ft, and so the area/space in question is
A = (1/2)(3.14)(25)^2
A = 981.3 ft^2
This is my go at the problem.
Let x be the original price.
72/100=6/100 of x.
so,
x=72/100 ÷ 6/100= $12.00
The answer is $12.00
Hope this helps!
A)
a+b=180 and a=2(b-30) using this in the first equation gives you:
2(b-30)+b=180
2b-60+b=180
3b-60=180
3b=240
b=80 so a=100
Andre's score was 100 and Brandon's score was 80.
b)
100x-200>50x-75 subtract 50x from both sides
50x-200>-75 add 200 to both sides
50x>125 divide both sides by 50
x>2.5
Answer:
Step-by-step explanation:
Acceleration is second derivative of distance and are related as:
Integrating both sides w.r.to t
Using initial value
We have to calculate the distance covered in time interval [0,5], so:
![\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft](https://tex.z-dn.net/?f=%5Cint%5Climits%5E5_0%20%5Cfrac%7Bds%7D%7Bdt%7D%3D%5Cint%5Climits%5E5_0%20%7B%5Cfrac%7B1%7D%7Bt%2B2%7D%7D%20%5C%2C%20dt%5C%5C%5C%5Cs%28t%29%3D%5Bln%7Ct%2B2%7C%5D%5E5_0%5C%5C%5C%5Cs%28t%29%3Dln%7C5%2B2%7C%2Bln%7C0%2B2%7C%5C%5C%5C%5Cs%28t%29%3D%28ln%7C7%7C%2Bln%7C2%7C%29%5C%2Cft)
