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3 years ago

Factor. 3n^4+21n^3+27n^2 Enter your answer in the box.

1 answer:

5 0

Factor the following:
3 n^4 + 21 n^3 + 27 n^2

Factor 3 n^2 out of 3 n^4 + 21 n^3 + 27 n^2:

Answer: 3 n^2 (n^2 + 7 n + 9)

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3 pens cost $2.70. What is the cost per pen?

marissa [1.9K]

2, 70$ : 3 = 0, 9o $The total cost for each pen
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3 years ago

Find the equation of the linear function represented by the table below in slope-intercept form.

alexandr402 [8]

Answer: The equation is y = 3x + 3

Step-by-step explanation:

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3 years ago

Chad drove 168 miles in 3 hours. How many miles per hour did Chad drive?

igor_vitrenko [27]

°° Let's see -

Basically, you divide the number of miles Chad drove by the number of hours it took. Then, it gives you the number of miles Chad drove in one hour. Let's try it!

168 ÷ 3 = 56

You can now see that Chad drove 56 miles in one hour.

↑ ↑ ↑ Hope this helps! :D

5 0

3 years ago

Read 2 more answers

Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)

Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

This is equal to the left hand side.

Thus, it is verified.

5 0

2 years ago

I'm reasking a previous question to make it more clear. This is a Linear Equation that I must solve. It includes fractions (the

Ugo [173]

Assuming the equation is:

$\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)$

When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.

Here the denominators are 2 and 10, hence the LCM is 10.

Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

$10\frac{x}{2}-10\frac{10x-25}{10}=10*3(x+3)-10(x-14)$

simplify, remember that there are always implied parentheses around numerators and denominators:

$5x-(10x-25)=30(x+3)-10(x-14)$

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

Simplify

-5x+25=20x+230

transpose terms

25-230=20x+5x

solve

x=-205/25=-41/5

In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

$\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)$

simplify, remember that there are always implied parentheses around numerators and denominators:

$2\frac{x}{2}-2\frac{2x-5}{2}=2*3(x+3)-2(x-14)$

$x-(2x-5)=6(x+3)-2(x-14)$

Now, distribute, i.e. remove parentheses and distribute:

$x-2x+5=6x+18-2x+28$

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

7 0

3 years ago

Read 2 more answers