Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Hello,
I believe it’s the last one
Answer:
4
Step-by-step explanation:
Because 3×4=12
The answer of
<span>-45+(-30)-90= -165
Hope this helps <3
</span>
The answer is $120, because you do;
0.40x = 48
YOU DIVIDE 48 ÷ 0.40 = 120
YOU'RE WELCOME ;)
