Yes it’s is a force multiplier
Answer:
A . Are the masses repelling or attracting
answer:
<em><u>So, positive energy densities ("masses") attract each other by gravitational interaction. This is the general idea.</u></em>
<em><u>B</u></em>. What is the magnitude of the electrical force between the objects<em><u>?</u></em>
<em><u>answer</u></em><em><u>:</u></em>
<em><u> </u></em><em><u>The magnitude of the electrostatic force F between two point charges q1 and q2 is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.</u></em>
C. What would the magnitude of the force be if one of the charges was 1/3 the amount?
answer:
<em><u>0.45</u></em>
D. ) What would the force be if the distance between the charges was only 1 meter (with the original charges)?
answer;
<em><u>Fmin=2.3×10^−28</u></em><em><u>N</u></em>
<em><u>E</u></em><em><u>:</u></em><em><u> </u></em>What would the force be if one of the charges was 1/3 the amount AND the distance was 1 meter?
answer;
<em><u>Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.</u></em>
<em><u>#</u></em><em><u>CARRYONLEARNING</u></em><em><u>:</u></em><em><u>)</u></em>
<em><u>LOVEUALL</u></em>
Answer:
+1.46×10¯⁶ C
Explanation:
From the question given above, the following data were obtained:
Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C
Force (F) = 0.615 N
Distance apart (r) = 0.750 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Charge 2 (q₂) =?
The value of the second charge can be obtained as follow:
F = Kq₁q₂ / r²
0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²
0.615 = 236700 × q₂ / 0.5625
Cross multiply
236700 × q₂ = 0.615 × 0.5625
Divide both side by 236700
q₂ = (0.615 × 0.5625) / 236700
q₂ = +1.46×10¯⁶ C
NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C
