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Black_prince [1.1K]
4 years ago
8

Which of saturn's moons has an atmosphere that is most like earth's?

Physics
2 answers:
AlladinOne [14]4 years ago
5 0

Answer:

Titan

Explanation:

ollegr [7]4 years ago
3 0
<span>Saturn's moon Titan has an atmosphere that is most like Earth's. Titan has clouds like earth. Titans atmosphere mostly consists Nitrogen and Methane. But Scientists have found that Titan as well consists of organic molecules that are formations of hydrogen and carbon which also includes oxygen and other elements which are evident for life as in Earth.</span>
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What type of ion is formed by a non-metal atom?
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Non metals produce something called protons they are ions 
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A student fills a tank of radius r with water to a height of h1 and pokes a small, 1.0 cm diameter hole at a distance h2 from th
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when a hole is made at the bottom of the container then water will flow out of it

The speed of ejected water can be calculated by help of Bernuolli's equation and Equation of continuity.

By Bernoulli's equation we can write

Po + \frac{1}{2}\rho v_1^2 + \rho g h = Po + \frac{1}{2}\rho v_2^2 + \rho g *0

Now by equation of continuity

A_1v_1 = A_2v_2

\pi (0.2)^2 v_1 = \pi (0.01)^2 v_2

from above equation we can say that speed at the top layer is almost negligible.

v_1 = 0

now again by equation of continuity

\rho g h = \frac{1}{2} \rho v^2

v = \sqrt{2 g h}

here we have

h = h_1 - h_2

h = 0.50 - 0.03 = 0.47m

now speed is given by

v = \sqrt{2* 9.8 * 0.47}

v = 3.03 m/s

7 0
3 years ago
The table below shows data of sprints of animals that traveled 75 meters. At each distance marker, the animals' times were recor
mr_godi [17]

Answer:

Explanation:

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5 0
3 years ago
Read 2 more answers
What is a description of compounds?
elena-14-01-66 [18.8K]
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To demonstrate the tremendous acceleration of a top fuel dragracer, you attempt to run your car into the back of a dragster that
noname [10]

Answer:

a. 2v₀/a   b. 2v₀/a  

Explanation:

a. Since you are moving with a constant velocity v₀, the distance, s you cover in time = t max is s = v₀t.

Since the dragster starts from rest with an acceleration, a, using

s' = ut + 1/2at² where u = 0 and s' = distance moved by dragster

s' = 0t + 1/2at²

s' = 1/2at²

Since the distance moved by me and the dragster must be the same,

s = s'

v₀t. =  1/2at²

v₀t. - 1/2at² = 0

t(v₀ - 1/2at) = 0

t= 0 or v₀ - 1/2at = 0

t= 0 or v₀ = 1/2at

t= 0 or t = 2v₀/a  

So the maximum time tmax = 2v₀/a

b. Since the distance covered by me to meet the dragster is s = v₀t in time, t = tmax which is also my distance from the dragster when it started. So, my distance from the dragster when it started is s =  v₀(2v₀/a)

= 2v₀/a  

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3 years ago
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