Question

Kinematics

Answer 1

Answer:

The acceleration and time are 1.95 m/s and 12.5 s.

Explanation:

Given that,

Speed = 80 ft/s =24.384 m/s

Distance = 500 ft =152.4 m

We need to calculate the acceleration

Using third equation of motion

$v^2-u^2= 2as$

$a = \dfrac{v^2-u^2}{2s}$

Where, u = initial velocity

v = final velocity

a = acceleration

s = distance

Put the value in the equation

$a=\dfrac{(24.384)^2-0}{2\times152.4}$

$a=1.95\ m/s^2$

We need to calculate the time

Using first equation of motion

$v=u+at$

$t =\dfrac{v-u}{a}$

$t=\dfrac{24.384-0}{1.95}$

$t =12.5\ s$

Hence, The acceleration and time are 1.95 m/s and 12.5 s.