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olya-2409 [2.1K]
3 years ago
11

Write an equation of the line that passes through the points (-2,-2) and (0,5)

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
&&(~ -2 &,& -2~) 
&&(~ 0 &,& 5~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-2)}{0-(-2)}\implies \cfrac{5+2}{0+2}\implies \cfrac{7}{2}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-2)=\cfrac{7}{2}[x-(-2)]
\\\\\\
y+2=\cfrac{7}{2}(x+2)\implies y+2=\cfrac{7}{2}x+7\implies y=\cfrac{7}{2}x+5
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If the Volume of a rectangular prism is 720 what is the width
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Answer:

The width of the rectangular prism is 9 cm.

Step-by-step explanation:

From the formula of the volume of a bar V=whl we see that w=\frac{V}{hl}=\frac{720}{8\cdot 10} = 9 cm.

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3 years ago
Factor completely 2x^3 + 6x^2 + 10x + 30
andrezito [222]

Answer:

The factored expression is 2(x² + 5)(x + 3).

Step-by-step explanation:

Hey there!

We can use a factoring technique referred to as "grouping" to solve this problem.

Grouping is used for polynomials with four terms as a quick and easy factoring method to remove the GCF and get down to the initial terms that create the expression/function.

Grouping works in the following matter:

  1. Given equation: ax³ + bx² + cx + d
  2. Group a & b, c & d: (ax³ + bx²) + (cx + d)
  3. Pull GCFs and factors

Let's apply these steps to the given equation.

  1. Given equation: 2x³ + 6x² + 10x + 30
  2. Group a & b, c & d: (2x³ + 6x²) + (10x + 30)
  3. Pull GCFs and factors: 2x²(x + 3) + 10(x + 3)

As you'll see, we have a common term with both sides of the expression. This term, (x + 3), is a valuable asset to the factoring process. This is one of the factors for our expression.

Now, we use our GCFs to create another factor.

  1. List GCFs: 2x², 10
  2. Create a term: (2x² + 10)

Finally, we'll need to simplify this one by taking another GCF, 2.

  1. Pull GCF: 2(x² + 5)

Now that we have this term, we need to understand that this <em>could</em> also be factored further using imaginary numbers, but it is also acceptable to leave it in this form.

Therefore, we have our final factors: 2(x² + 5) and (x + 3).

However, when we factor, we place all of our terms together. This leaves us with the final answer: 2(x² + 5)(x + 3).

7 0
2 years ago
The graph of the function f(x) is shown below. On a coordinate plane, a curved line with a minimum value of (0.6, 2.5) and a max
statuscvo [17]

Answer:-1.8 do good on the rest of your test`

Step-by-step explanation:

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3 years ago
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What is the volume of this prism?<br> Enter your answer in the box.
jarptica [38.1K]

Short Answer: 560 cm squared

Long Answer:

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2 years ago
How do I find the y intercept in a fraction
Furkat [3]

ANSWER:

Both functions have the same slope

The linear equation does not have a y-intercept

The table and the grahp express an equivalent function

STEP-BY-STEP EXPLANATION:

In order to compare, we must calculate the slope of the table, knowing that the equation in its slope and intercept form is the following:

\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}

The formula to calculate the slope is the following:

m=\frac{y_2-y_1}{x_2-x_1}

The points are (-6, -9/2) and (4,3), replacing:

m=\frac{3-(-\frac{9}{2})}{4-(-6)}=\frac{3+\frac{9}{2}}{4+6}=\frac{\frac{15}{2}}{10}=\frac{15}{20}=\frac{3}{4}

The slope is 3/4

Now, for b

x = 4

y = 3

m = 3/4

replacing:

\begin{gathered} 3=\frac{3}{4}\cdot4+b \\ b=3-3 \\ b=0 \end{gathered}

The equation is:

y=\frac{3}{4}x

Therefore, the true statements are:

• Both functions have the same slope

,

• The linear equation does not have a y-intercept

,

• The table and the grahp express an equivalent function

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