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2 years ago

Find the value of x so that the line through the pair of points has the given slope.

Mathematics

1 answer:

MatroZZZ [7]2 years ago

3 0

1 is the answer b/c that's the only number it goes too

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A candy jar has 24 candies. One-third of the candies are chocolates. Of the leftover candies, half are gummy bears and the other

Dennis_Churaev [7]

8 skittles hope this helps

8 0

2 years ago

7. 3х + 3 = 3(х + 1)

Alik [6]

X=0
Hopefully this helps

5 0

2 years ago

For the functions f(x) = x^2+ 8x + 2 and g(x) = -5+9, find (f•g)(x)and (f.g)(-1).

Ne4ueva [31]

Answer: (f·g)(x) = -5x³ - 31x² + 62x + 18

(f·g)(-1) = -70

(fog)(x) = 25x² - 130x + 155

(fog)(-1) = 310

Step-by-step explanation:

f(x) = x² + 8x + 2 g(x) = -5x + 9

(f·g)(x) = (x² + 8x + 2)(-5x + 9)

= -5x³ + 9x²

- 40x² + 72x

- 10x + 18

= -5x³ - 31x² + 62x + 18

(f·g)(-1)= -5(-1)³ - 31(-1)² + 62(-1) + 18

= -5(-1) - 31(1) - 62 + 18

= 5 - 31 - 62 + 18

= -70

****************************************************************************************

(fog)(x) = (-5x + 9)² + 8(-5x + 9) + 2

= 25x² - 90x + 81

- 40x + 72

+ 2

= 25x² - 130x + 155

(fog)(-1) = 25(-1)² - 130(-1) + 155

= 25 + 130 + 155

= 310

It wasn't clear if you wanted multiplication or composition so I solved both.

6 0

3 years ago

Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0

3 years ago

Read 2 more answers

Need help (midpoints)

Zinaida [17]

Answer:

Step-by-step explanation:

i know it

5 0

2 years ago