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Dima020 [189]
3 years ago
7

Which of the following sets represents a function?

Mathematics
2 answers:
Nikolay [14]3 years ago
6 0

A function is a special relationship where each input has a single output.

A. The set {(3, 5), (-1, 7), (3, 9)} doesn't represent a function, because input x=3 has two outputs y_1=5 and y_2=9.

C. The set {(1, 2), (1, 4), (1, 6)} doesn't represent a function, because input x=1 has three outputs y_1=2, y_2=4 and y_3=6.

B. The set {(1, 2), (3, 2), (5, 7)} represents a function, because each input has a single output.

Answer: correct choice is B.

Agata [3.3K]3 years ago
4 0

A data set can be verified to be a function or not through the vertical line test. In this test, if the data set has points lying on the same vertical line, then it is not a function. This means the points should not have the same x. The answer hence to the problem is B. 
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Answer:

The Axes. The independent variable belongs on the x-axis the(horizontal line) of the graph and the dependent variable belongs on the y-axis the (vertical line)

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3 years ago
Linda scored 35, 47, and 42 points on three tests. How many points should she get on the fourth test to get an average score of
Taya2010 [7]
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4 years ago
The parking garage has 9 rows with 10 parking space in each row . There are 8 empty space . How many space are filled.
tatiyna

Answer:

82 .

Step-by-step explanation:

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7 0
3 years ago
The first step for deriving the quadratic formula from the quadratic equation, 0 = ax2 bx c, is shown.step 1: –c = ax2 bxwhich b
Ksju [112]

Answer:

option (b) is correct.

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Step-by-step explanation:

Given : the quadratic equation ax^2+bx+c=0

We have to find the first step for deriving the quadratic formula from the quadratic equation.

Quadratic formula  is given by \frac{-b\pm\sqrt{b^2-4ac}}{2a}

Consider the given quadratic equation ax^2+bx+c=0

Divide the equation by a, we get,

x^2+\frac{b}{a}x+\frac{c}{a}=0

Take \frac{c}{a} to other side, we get,

x^2+\frac{b}{a}x=-\frac{c}{a}

Add (\frac{b}{2a})^2 to both side, we get,

x^2+\frac{b}{a}x+(\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}

Thus, the left side is in the form of (a+b)^2=a^2+b^2+2ab

On solving, we get,

(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}

Then solve for x , we get quadratic formula \frac{-b\pm\sqrt{b^2-4ac}}{2a}

Thus, first step to solve for deriving the quadratic formula from the quadratic equation is completing the square.

Thus, option (b) is correct.

3 0
3 years ago
Read 2 more answers
Find x in this 45°-45°-90° triangle. <br> x =
hichkok12 [17]

Answer:

Step-by-step explanation:

x= -90 degrees

8 0
2 years ago
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