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DedPeter [7]
3 years ago
9

Calculate the area of kite PQRS.

Mathematics
2 answers:
Sonbull [250]3 years ago
6 0
Check the picture below

so, just get the area of each triangle, and sum them up, that's the area of the kite

Bogdan [553]3 years ago
4 0
A=1/2[(15+23)*(8+8)]
   =1/2(608)
   =304
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How are central tendency and standard deviation related
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Answer:

Measure of central tendency is a value that represents a typical, or central, entry of a data set. The most common measures of central tendency are: • Mean (Average): The sum of all the data entries divided by the number of entries. ... The standard deviation measure variability and consistency of the sample or population.

Step-by-step explanation:

5 0
3 years ago
14 POINTS ASAP WHAT IS THE MEASURE OF ANGLE A
sashaice [31]
Wow...we have lots of numbers to go through.  we know that a 6 sided figure is a hexagon and the interior angles add up to be 720°. so.....

∠A + ∠B + ∠ C + ∠D + ∠E + ∠F = 720°
(x - 60) + (x - 40) + 130 + 120 + 110 + (x - 20) = 720
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x = 160                  (divided both sides by 3)

put the value of x into ∠A  (x - 60) = 160 - 60 = 100

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7 0
3 years ago
Solve for x in simplest radical form. 2x2 + 2x + 4 = x2 + 6x + 5
devlian [24]

Answer:

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7 0
3 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
3 years ago
Adding fractions with unlike denominators<br>​
insens350 [35]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
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