Answer:
The answer is B. 5/8 quarts
Step-by-step explanation:
1 ounce is equal to .03125 quarts so to find the amount of quarts, you multiply 20 times .03125 to get .625 or 5/8.
The solve for n would be 11
2 to the second power is 4 and 4x11=44
36% of 24..... or 0.36 times 24= 8.64
22% of 24......or 0.22 times 24= 5.28
8.64-5.28= 3.36. D.
Answer:
sqrt(277) =x
x is approximately 16.64331698
Step-by-step explanation:
This is a right triangle since 14 is tangent to the circle and 9 is a radius
We can use the Pythagorean theorem to solve this problem
a^2 +b^2 =c^2
9^2+14^2 =x^2
81+196 = x^2
277 = x^2
Taking the square root of each side
sqrt(277) = sqrt(x^2)
sqrt(277) =x
The correct answer is: [D]: "17" .
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The radius is: " 17" .
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Note:
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The formula/equation for the graph of a circle is:
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(x − h)² +<span> </span> (y − k)² = r² ;
in which:
" (h, k) " ; are the coordinate of the point of the center of the circle;
"r" is the length of the "radius" ; for which we want to determine;
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We are given the following equation of the graph of a particular circle:
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→ (x − 4)² + (y + 12)² = 17² ;
which is in the correct form:
→ " (x − h)² + (y − k)² = r² " ;
in which: " h = 4 " ;
" k = -12" ;
"r = 17 " ; which is the "radius" ; which is our answer.
→ { Note that: "k = NEGATIVE 12" } ;
→ Since the equation <u>for this particular circle</u> contains the expression: _________________________________________________________
→ "...(y + k)² ..." ;
[as opposed to the standard form: "...(y − k)² ..." ] ;
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→ And since the coordinates of the center of a circle are represented by:
" (h, k) " ;
→ which are: " (4, -12) " ; (<u>for this particular circle</u>) ;
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→ And since: " k = -12 " ; (<u>for this particular circle</u>) ;
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then:
" [y − k ] ² = [ y − (k) ] ² = " [ y − (-12) ] ² " ;
= " ( y + 12)² " ;
{NOTE: Since: "subtracting a negative" is the same as "adding a positive" ;
→ So; " [ y − (-12 ] " = " [ y + (⁺ 12) ] " = " (y + 12) "
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Note: The above explanation is relevant to confirm that the equation is, in fact, in "proper form"; to ensure that the: radius, "r" ; is: "17" .
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→ Since: "r = 17 " ;
→ The radius is: " 17 " ;
which is: Answer choice: [D]: "17" .
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