The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
n=2
2(n+8)=20
2n+16=20
-16 -16
<u>2n=4</u>
2 2
n= 2
There u go love
Step-by-step explanation:
So all you have to do to find out how much she had before is add up both value 12.50+34.25= 46.75$ (answer)
because y-12.50=34.25 so you would have to had the 12.5 to the other side to find the value of Y
well if you can find the slope then choose one of your ordered pair and plug them in tot he corresponding variable. since you don't know what the y intercept you basically find x which will be the y int.
We are given the bounds of x so after calculation
144 is the answer
