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irina1246 [14]
2 years ago
11

How many possible outcomes are there on ryan's first turn flipping two cards?

Mathematics
1 answer:
GalinKa [24]2 years ago
3 0

The possible outcomes are there on Ryan's first turn flipping two cards is

<h3>What are cards?</h3>

The cards are 52 in number in which 13 cards are different. Each card is four in quantity.

Ryan is playing a multiplication game with a pile of 26 cards, each with a number on them.

Each turn, he flips over two of the cards and has to  multiply the numbers.

The  number of ways in which two cards can be selected  from 26 cards, at the same time. The order of those are important.

Then, the number of possible outcomes on each flip of two cards

= 26 p(2)

= 26 x 25

=650

Thus, the possible outcomes are there on Ryan's first turn flipping two cards.

Learn more about cards.

brainly.com/question/7570270

#SPJ1

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Answer:

C

Step-by-step explanation:

PEMDAS, Parenthesis comes first. Since multiplication is in the parenthesis this means that it's multiplication first.

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8x1 4* 28 × +8 help me ​
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Answer:

8x1 4* 28 × +8 = 28x + 12

8x^1 + 4 times 28 + 8

Add common Factors which are 8x and 28x added they equals 36x and 4 and 8 which equals 12 so now we got 28x + 12 and that is the answer

<u>PLEASE GIVE BRAINLIEST THANK YOU!!!</u>

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1 year ago
A number n is multiplied by -5 /8 the product is -0.4 what is the value of n
tankabanditka [31]

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Step-by-step explanation:

hope this helped :)

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BRAINLIEST!! HELP.. <br> 4. Simplify the given expression.
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Answer:

\frac{( {x}  + 1) (x - 1)(16 {x}  - 37)}{( {x}^{2}  + 2)}

Step-by-step explanation:

\frac{ \frac{3 {x}^{2} - 3 }{x} }{ \frac{3( {x}^{2}  + 2)}{16 {x}^{2} - 37x }  \\  \\  =  \frac{3( {x}^{2} - 1) }{x}  \times  \frac{x(16 {x} } - 37)}{3( {x}^{2}  + 2)}  \\  \\  =  \frac{3( {x}  + 1) (x - 1)}{x}  \times  \frac{x(16 {x} - 37)}{3( {x}^{2}  + 2)} \\  \\  = \frac{( {x}  + 1) (x - 1)}{1}  \times  \frac{(16 {x} - 37)}{( {x}^{2}  + 2)} \\  \\  = \frac{( {x}  + 1) (x - 1)(16 {x}  - 37)}{( {x}^{2}  + 2)}

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Please help 100 points + brainlest<br> Look at the pictures below and answer them
PolarNik [594]

Answer:

the answers are bolded below!

Step-by-step explanation:

1. y-y1=m(x-x1)

line one- 14-4/6-1 = 10/5 = 2

so....     y-1=2(x-4)

simplified     y=2x-7

line two- -2-23/1-6 = -25/5 = -5

so.....      y-6=-5(x-23)

simplified         y=-5x+121

b- they will intersect 1 time at (18.2,29.5)

2. No, it the system has infinitely many solutions, then the lines would be on top of each other. But since there are only two solutions, then your answer would not be infinitely many solutions.

3. y=-2x+1. This would not intersect with y=-2x+3 because they are parallel. the slopes are the same so they will each travel at the same rate but they have different y intercepts.

4. y=-2x+7 ------> x=-1/2y-7/2

y=-3(-1/2y+7/2)+8  -----> y=5

y=-2x+7 --->   5=-2x+7  ----> x=1

one solution at (1,5) because f graphed, the lines would only intersect once.

b- x=5

3x-y=5   --->   3(5)-y=5   --->   y=10

one solution at (5,10) because f graphed, the lines would only intersect once.

c- no solutions because if it were to be graphed, the lines would not intersect at all.

d- no solutions because if it were to be graphed, the lines would not intersect at all.

e- no solutions because if it were to be graphed, the lines would not intersect at all.

<em>i am in algebra two so you can trust my answer. If you need more help lmk in the comments. Happy holidays and stay safe!</em>

6 0
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