Question

BRAINLIEST!! HELP.. 4. Simplify the given expression.

Answer 1

Answer:

$\frac{( {x} + 1) (x - 1)(16 {x} - 37)}{( {x}^{2} + 2)}$

Step-by-step explanation:

$\frac{ \frac{3 {x}^{2} - 3 }{x} }{ \frac{3( {x}^{2} + 2)}{16 {x}^{2} - 37x } \\ \\ = \frac{3( {x}^{2} - 1) }{x} \times \frac{x(16 {x} } - 37)}{3( {x}^{2} + 2)} \\ \\ = \frac{3( {x} + 1) (x - 1)}{x} \times \frac{x(16 {x} - 37)}{3( {x}^{2} + 2)} \\ \\ = \frac{( {x} + 1) (x - 1)}{1} \times \frac{(16 {x} - 37)}{( {x}^{2} + 2)} \\ \\ = \frac{( {x} + 1) (x - 1)(16 {x} - 37)}{( {x}^{2} + 2)}$

Answer 2

Answer:

C

Step-by-step explanation:

Simplify the numerator/ denominator

$\frac{3x^2-3}{x}$ ← factor out 3 from each term on the numerator

= $\frac{3(x^2-1)}{x}$ ← factor (x² - 1) as a difference of squares

= $\frac{3(x+1)(x-1)}{x}$

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$\frac{3(x^2+2)}{16x^2-37x}$ ← factor out x from each term on the denominator

= $\frac{3(x^2+2)}{x(16x-37)}$

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  $\frac{3(x+1)(x-1)}{x}$ ÷ $\frac{3(x^2+2)}{x(16x-37)}$

To divide the expressions

Leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

$\frac{3(x+1)(x-1)}{x}$ × $\frac{x(16x-37)}{3(x^2+2)}$

Cancel the x's and the 3's on the numerator/ denominator, leaving

$\frac{(x+1)(x-1)(16x-37)}{x^2+2}$ → C