What is 4 - 7f = f - 12

1 answer:

6 0

4 - 7f = f - 12

Subtract f from both sides.

4 - 7f - f = -12

Subtract 4 from both sides.

-7f - f = -12 - 4

Simplify.

-8f = -16

Divide both sides by -8.

f = 2

To show your work, simply plug in the value of f into the original equation.

When f = 2, :

4 - 7f = f - 12

4 - 7(2) = (2) - 12

Simplify.

4 - 14 = 2 - 12

Simplify.

-12 = -12

So, f = 2

~Hope I helped!~

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Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$