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olchik [2.2K]
3 years ago
12

What is 4 - 7f = f - 12

Mathematics
1 answer:
forsale [732]3 years ago
6 0
4 - 7f = f - 12

Subtract f from both sides.

4 - 7f - f = -12

Subtract 4 from both sides.

-7f - f = -12 - 4

Simplify.

-8f = -16

Divide both sides by -8.

f = 2

To show your work, simply plug in the value of f into the original equation.

When f = 2, :

4 - 7f = f - 12

4 - 7(2) = (2) - 12

Simplify.

4 - 14 = 2 - 12

Simplify.

-12 = -12

So, f = 2

~Hope I helped!~


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Answer:

1/3

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2) 2 and 6 can both be divide be 2.

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The cheerleading team is doing a car wash for a fundraiser. They are able to wash an average of 1 1/2 cars each 1/6 hour. What i
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Find the point at which the line joining the two points (-3,-5) and (7,5) cuts they y axis
8090 [49]

Answer:

(0,-2)

Step-by-step explanation:

First we find the equation of the line passes through (-3,-5) and (7,5).

The slope of the line is

m=\frac{5-(-5)}{7-(-3)}\\=\frac{10}{10}\\=1

So by the point slope formula the equation of the line is

y-5=1(x-7)\\y=x-7+5\\y=x-2

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4 0
2 years ago
Find f'(x) and state the domain of f':<br> f(x) = In (2x^2+1)
-Dominant- [34]

Answer:

f'(x) = \frac{4x}{2x^2+1}

Domain: All Real Numbers

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = ln(2x² + 1)

<u>Step 2: Differentiate</u>

  1. Derivative ln(u) [Chain Rule/Basic Power]:                          f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}
  2. Simplify:                                                                                       f'(x) = \frac{1}{2x^2+1} \cdot 4x
  3. Multiply:                                                                                                     f'(x) = \frac{4x}{2x^2+1}

<u>Step 3: Domain</u>

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.

5 0
3 years ago
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slamgirl [31]

Answer:

10%

Step-by-step explanation:

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