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Mariana [72]
3 years ago
7

-2b(-7)=11 =============

Mathematics
2 answers:
boyakko [2]3 years ago
4 0

Answer:

Solution given:

-2b(-7)=11

open bracket

-2b*-7=11

+14b=11

divide both side by 14

14b/14=11/14

b=11/14

Lubov Fominskaja [6]3 years ago
3 0

Answer:

- 2b ( - 7) = 11 \\  - 2b \times  - 7 = 11 \\ 14b = 11 \\ b =  \frac{11}{14}  \\ thank \: you

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3 years ago
We have a right triangle that has am 8 meter and 21 meter leg .Find the hypotenuse
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Answer:

hypotenuse is 22.47 m

Step-by-step explanation:

The length of both legs of a right angle triangle are 8m and 21 m

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To find hypotenuse we use Pythagorean theorem

Hypotenuse is AC  and other two legs are AB  and BC

AC^2 = AB^2 + BC^2

Hypotenuse ^2 = 8^2 + 21^2

hypotenuse = \sqrt{8^2 + 21^2}

= \sqrt{64 + 441}

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3 years ago
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3 years ago
Two poles are connected by a wire that is also connected to the ground. The first pole is 18 ft tall and the second pole is 24 f
9966 [12]

Answer:

  72 feet from the shorter pole

Step-by-step explanation:

The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.

The shorter pole height as a fraction of the total pole height is ...

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so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:

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_____

<em>Comment on the problem</em>

This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.

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Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:

  L = √(18²+x²) + √(24² +(168-x)²)

and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.

7 0
3 years ago
X y
xenn [34]
B) y = 4x

X| * |Y|
2|2*4|8 |
3|3*4|12|
4|4*4|16|
5|5*4|20|
7 0
4 years ago
Read 2 more answers
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