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professor190 [17]
2 years ago
9

What is the average rate of change for this quadratic function for the interval fr x=2 to x=4?

Mathematics
1 answer:
myrzilka [38]2 years ago
8 0

Answer:

0-4

derivate first

function is missing

substitute the value of X

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What side lengths should be used to model the rectangle
Bas_tet [7]
Well there aren’t any pictures so yea
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3 years ago
The light intensity I​ (in lumens) at a depth of x feet in Lake Elizabeth is given by the formula log (StartFraction Upper I Ove
antiseptic1488 [7]

Answer:

The light intensity at a depth of 24 feet is 3.0143 lumens.

The light intensity will be 7 lumenus at the depth of 9.3732 feet approximately.

Step-by-step explanation:

Consider the provided formula.

log(\frac{I}{12})=-0.025x

Where I is the intensity of light and x is the depth.

Part (A) Find the light intensity at a depth of 24 feet.

Substitute x=24 in above formula.

log(\frac{I}{12})=-0.025(24)

log(\frac{I}{12})=-0.6

\frac{I}{12}=10^{-0.6}

\frac{I}{12}=0.2512

I=3.0143

Hence, the light intensity at a depth of 24 feet is 3.0143 lumens.

Part (B) At what depth is the light intensity 7 ​lumens

Substitute I=7 in above formula.

log(\frac{7}{12})=-0.025x

-0.23433=-0.025x

0.23433=0.025x

x=\frac{0.23433}{0.025}

x=9.3732

Hence, the light intensity will be 7 lumenus at the depth of 9.3732 feet approximately.

3 0
3 years ago
What is 10/12 as a decimal ?
ZanzabumX [31]
<span>0.833333333333333 is the answer</span>
5 0
3 years ago
Read 2 more answers
HOW TO DO THIS QUESTION PLEASE ​
Mariulka [41]

Answer:

Try 5 first. If that is marked wrong, try 5.07

Step-by-step explanation:

Estimate means put your calculator on the other side of the room. You are to do this in your head.

78 is nearly 80

69 is nearly 70

29 is nearly 30

So now do the question

80 + 70 = 150       because 8 and 7 = 15.

150 / 30 = 50 because 15/3 = 5

So the answer that should be right for this question should be 5

Let's see how close that is.

78 + 69 = 147

147 / 29 = 5.07

4 0
3 years ago
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Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ&lt;2π. secant StartFraction 5 theta Over 4 En
qaws [65]

Answer:  4π/15, 4π/3 and 28π/15 (in radians)

Step-by-step explanation:

sec 5\theta/4 =2

Recall that sec \theta = 1/cos \theta

1/cos (5\theta/4) =2

cos (5\theta/4) =1/2

Cos^{-1} \frac{1}{2} = 5\theta/4

This implies that

\mp60+360n=5\theta/4

\theta=4/5(\mp60+360n)= \mp48+288n

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Therefore the values of \theta between 0 and 2π are 48, 240 and 336. (All in degrees)

48 degrees= 4π/15 rad

240 degrees =4π/3 rad

336 degrees = 28π/15 rad

5 0
3 years ago
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