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3 years ago

1 yard = 3 feet and 1 mile = 5280 feet, how many yards are there in 3 miles?

2 answers:

5 0

Answer: 5280 yards

Explanation: There are 1760 yards in a mile. So to find out how many yards there are in 3 miles, you multiply 3 by 1760 and you get 5280 yard.

Debora [2.8K]3 years ago

3 0

Answer:

3 Yards

Step-by-step explanation: If 1 yard = 1 multiply by 3 to get ~ 3 Yards.

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BRAINIEST! HELP !The ratio of the base and height of a rectangle is 3 to 8. The perimeter of the rectangle is 138.6 cm. (6 point

steposvetlana [31]

B/h=3/8
8b=3h
8/3b=h
P=2(h+b)
P=138.6

138.6=2(h+b)
divide both sides by 2
69.3=h+b
suub (8/3)b for h
69.3=(8/3)b+b
times both sides by 3 to get rid of fraction
207.9=8b+3b
207.9=11b
divide both sides by 11
18.9=b

sub back

(8/3)b=h
(8/3)18.9=h
50.4=h

area=height times base
aera=50.4 times 18.9
aera=952.56 cm²

1. base=18.9 cm
2. height=50.4 cm
3. area=952.56 cm²

3 0

3 years ago

20(base three)-11(base three) . Carry out the operation in binary system

bija089 [108]

20₃ - 11₃ = 20₃ - 10₃ - 1₃

… = 10₃ - 1₃

… = 2₃

Put another way, we "borrow a 1" from the 3¹ digits place:

20₃ = 1(3)₃ - 11₃ = 2₃

But this is just the number 2 (in base 10), which in base 2 would be 10₂.

4 0

2 years ago

What is the answer to this equation6+3/34+21/2=

malfutka [58]

Answer:

282/17

Step-by-step explanation:

6+3/34 =207/34

and 207/34+21/2=282/17

3 0

3 years ago

Everyone wants to watch football games on Thanksgiving. There are 3 games on in afternoon and 3 on at night. How many different

Vikki [24]

Answer:

Step-by-step explanation:

At afternoon there are 3 games, lets call them A1, A2, and A3. These are simultaneous, which means you can ONLY watch one of them.

At night there are other three, lets call them N1, N2 and N3. Which again, are simultaneous, so you need to chose only one.

So, you can, at most, watch 2 games: one in the afternoon (extracted from the set {A1, A2, A3}) and one at night (extracted from the set {N1, N2, N3}).

So, here what you need is ALL the possible combinations between afternoon and games. As thee choices are independent, this is, the game chosen at afternoon has no effect on the night decision, we can just multiply the number of options in every set: 3*3 = 9. So there are 9 different combinations, which are:

A1 N1, A1 N2, A1 N3, A2 N1, A2 N2, A2 N3, A3 N1, A3 N2, A3 N3.

Here I supposed you watch a game in both, night and afternoon. If you can choose to NOT watch any game, the sets will have 4 elements but the reasoning is equal.

7 0

3 years ago

15PTS QUICK

lana66690 [7]

Answer:

Option B

40x + 50y = 130

5x - 4y = 16

Option C

20x + 25y = 65

-20x + 16y = 64

Step-by-step explanation: