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zmey [24]
1 year ago
13

Adam is training a group of cyclists. Each cyclist completes a 10-kilometer time trial during training. Adam records the times,

in minutes, below.
12:32, 12:46, 13:30, 15:03, 13:43, 13:46, 14:20, 14:29, 12:34, 14:43, 15:26, 16:02, 16:16, 14:38, 16:55, 17:10, 14:26, 17:21, 17:58, 13:30 Which histogram shows the results of the time trial?

Mathematics
1 answer:
nydimaria [60]1 year ago
7 0

The histogram which shows the results of the time trial is option B

<h3>Histogram</h3>

Given data:

12:32, 12:46, 13:30, 15:03, 13:43, 13:46, 14:20, 14:29, 12:34, 14:43, 15:26, 16:02, 16:16, 14:38, 16:55, 17:10, 14:26, 17:21, 17:58, 13:30

Grouping of data,:

12:00 - 12:59 = 3

13:00 - 13:59 = 4

14:00 - 14:59 = 5

15:00 - 15:59 = 2

16:00 - 16:59 = 3

17:00 - 17:59 = 3

  • The frequency is represented on the y-axis(number of cyclist)
  • The time is represented on the x-axis

Learn more about histogram:

brainly.com/question/9388601

#SPJ1

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Yeah please help
nydimaria [60]

Answer:

6 poinnts per question

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Michaela is planning a pizza party for 48 people. she has $200 to buy pizza and soda for the party. Each 12-pack of soda can cos
Dominik [7]
The answer to this question would be: D. <span>200>6P(8.00)+4S(5.00)
</span>

Michaela is planning a pizza party for 48 people and she uses 12-pack of soda and <span>8-slice pizza. That means the pack of soda she needs would be:
48 people/ (12soda/pack)= 4 pack

Then, number the pizza she needs:
48 people/ 8 (slice/pizza)=  6 pizza

She has $200 so the price she can afford should be lower than that. The function would be:
the money she has > number of pizza(price of pizza) + number of soda(price of soda)
</span>200>6P(8.00)+4S(5.00)
7 0
3 years ago
Read 2 more answers
You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
What is the domain of the relation? {x| x = –4 , 0, 1, 2}. {x| x = –7, –6, 2, 11, 3}. {y| y = –4, 0, 1, 2}. {y| y = –7, –6, 2, 1
sukhopar [10]

Answer:

The correct answer B on ED

Step-by-step explanation:

5 0
2 years ago
$2 increased by 8.5%
Taya2010 [7]
You multiply 2 by 0.085 and you get the answer
$0.17
Then add $0.17 and $2 and you get $2.17
8 0
3 years ago
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