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Wittaler [7]
3 years ago
13

Diameter of a sphere with the volume of 972πft^3

Mathematics
1 answer:
pogonyaev3 years ago
6 0
\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}~~
\begin{cases}
r=radius\\
-----\\
V=972\pi 
\end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 972\pi }{4\pi }=r^3
\\\\\\
729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}

now, recall that a diameter is twice as long as the radius, so the diameter is 2r.
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Adam currently runs about 20 miles per week, and he wants to increase his weekly mileage by 20%. How many miles will Adam run pe
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Answer:

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3 0
3 years ago
Sue has 20 biscuits in a tin There are 12 plain biscuits 5 chocolate biscuits 3 currant biscuits Sue takes at 2 random biscuits
vagabundo [1.1K]

Answer:

111 / 190

Step-by-step explanation:

Total biscuits = 20

Plain, P = 12

Chocolate, C = 5

Currant, K = 3

Assume without replacement :

Probability that biscuit are of the same type :

P(plain) :

12 / 20 * 11 / 19 = 132 / 380

P(chocolate) :

5/ 20 * 4 / 19 = 20/ 380

P(currant) :

3/20 * 2 /19 = 6 / 380

Therefore,

Probability that biscuit is of the same type :

P(plain) + P(chocolate) + P(currant)

132/380 + 20/380 + 6/380

158 / 380 = 79 / 190

Therefore, probability that biscuit aren't of the same type :

1 - P(biscuit is of same type)

1 - 79/190

(190 - 79) / 190

111 / 190

7 0
2 years ago
i really need help with my math assignment it’s normal distributions and i need this to graduate tomorrow if anyone can help it
Vika [28.1K]
Where’s the work you need help with :)
7 0
3 years ago
Find the sum or different 11/18-1/6
ira [324]

Answer:

4/9

Step-by-step explanation:

11/18-1/6


The first step is to get a common denominator, which is 18.  We can multiply 1/6 by 3/3 to get the denominator to 18


11/18 - 1/6 *3/3

11/18 - 3/18

8/18

Now we can simplify the fraction by dividing the top and bottom by 2

4/9

7 0
3 years ago
Read 2 more answers
Use multiplication to find three ratios equivalent to 8:12
tatyana61 [14]
Ok so 8:12 can be 8 to 12, or 8\12

do that help?
4 0
3 years ago
Read 2 more answers
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