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Wittaler [7]
3 years ago
13

Diameter of a sphere with the volume of 972πft^3

Mathematics
1 answer:
pogonyaev3 years ago
6 0
\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}~~
\begin{cases}
r=radius\\
-----\\
V=972\pi 
\end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 972\pi }{4\pi }=r^3
\\\\\\
729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}

now, recall that a diameter is twice as long as the radius, so the diameter is 2r.
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Remember how this works:

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Let's analyze the sentences:

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This is true, when x = 0 we have:

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2) "Domain: (-∞,∞); Range: [0,∞)"

This is also true, we clearly do not have any restriction in the domain.

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3) "(0, 0) is the minimum point."

Now, as x increases in the positive range, also does the value of y.

And as x decreases in the negative range, as the absolute value changes the sign, we will also have an increase in the value of y.

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4) "The graph has a line of symmetry at y = 0."

This is false.

The real line of symmetry is at x = 0, y = 0 corresponds to the x-axis, and as the graph opens up, we can not have symmetry about any line parallel to the x-axis.

4 0
4 years ago
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dalvyx [7]

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Step-by-step explanation:

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3 years ago
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polet [3.4K]
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4 years ago
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frez [133]

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Step-by-step explanation:

Factor using difference of cubes and set each factor equal to 0.

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3 years ago
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MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

Your answer

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Mark it as Brainlist answer. Follow me.

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