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2 years ago

8

An ant crawled 12 inches in 10 seconds. A second ant crawled 24 inches in 10 seconds. Calculate the speed of each ant, then comp

are the 2 by telling which one is faster.

1 answer:

Charra [1.4K]2 years ago

6 0

Answer:

Step-by-step explanation:divide 12/10 and 24/10. The larger answer will tell you the slower ant... I’m pretty sure

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there are 2 ones, 1 five,3tens, and 1 twenty. if there are 28 bills in her wallet, what would you predict is the approximate val

Kruka [31]

There would be 8 ones, 4 fives, 12 tens, and 4 twenties. That together would be about $228

4 0

3 years ago

A manufacturer knows that their items have a normally distributed length, with a mean of 15.4 inches, and standard deviation of

Masteriza [31]

Answer:

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 15.4 inches, and standard deviation of 3.5 inches.

This means that $\mu = 15.4, \sigma = 3.5$

16 items are chosen at random

This means that $n = 16, s = \frac{3.5}{\sqrt{16}} = 0.875$

What is the probability that their mean length is less than 16.8 inches?

This is the p-value of Z when X = 16.8. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{16.8 - 15.4}{0.875}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452.

0.9452 = 94.52% probability that their mean length is less than 16.8 inches.

5 0

2 years ago

Carly's age is more than twice his sisters age, s. Which of the following expressions represents Carly's age? (A) 2s + 3 (B) 3s

Ilya [14]

I would say A.

B would be Carly's age is two years more than three times his sister's age.

C would be Carly's age is two times his sister's age plus three

D would be Carly's age is his sister's age squared plus three.

5 0

2 years ago

Read 2 more answers

Which value is equivalent to 3 x 12 / ( 4 + 2)<br><br>A 6<br><br>B 11<br><br>C 12<br><br>D 15

konstantin123 [22]

3x12/(4+2)

36 divided by 6 = 6

Your answer is A 6

8 0

2 years ago

The burges are moving across the country .Mr burges leaves 3 hours before mrs.burges. If he averages 50 mph and she averages 70

kirill [66]

10.5 hours

let t be time then distance travelled by both is

Mr Burges ⇔ d = 50t ( distance = speed × time )

Mrs Burges ⇒ d = 70(t - 3)

At the point of overtaking both will have travelled the same distance

equating their distance and solving for t

70(t - 3) = 50t

70t - 210 = 50t ( subtract 50t from both sides )

20t - 210 = 0 ( add 210 to both sides )

20t = 210 ( divide both sides by 20 )

t = 10.5 hours

4 0

3 years ago