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jeka57 [31]
2 years ago
15

Find [-4/5]×3/7×15/16×[-14/9]​

Mathematics
2 answers:
Ganezh [65]2 years ago
8 0

Answer:

<h3>\frac{1}{2}</h3><h3 /><h3 />

Step-by-step explanation:

<h3 /><h3>[- 4/5] [- 14/9] = 56/45</h3>

<h3>= 56/45×3/7×15/16</h3><h3 /><h3>1. Apply the fraction rule : <u>a</u> × <u>c</u> = <u>a </u><u>×</u><u> </u><u>c</u></h3><h3> b d. b d</h3><h3 /><h3>=  \frac{56 \times 3 \times 15}{45 \times 7 \times 16}</h3><h3 /><h3>2. Factor the number : 56 = 7 ×8</h3>

<h3>=  \frac{7 \times 8 \times 3 \times 15}{45 \times 7 \times 16}</h3><h3 /><h3>3. Cancel the common factor : 7</h3>

<h3>=  \frac{8 \times 3 \times 15}{45 \times 16}</h3><h3 /><h3>3. Factor the number : 16 = 8 × 3</h3>

<h3>=  \frac{8 \times 3 \times 15}{45 \times 8 \times 2}</h3><h3 /><h3>4. Cancel the common factor : 8</h3>

<h3>=  \frac{3 \times 15}{45 \times 2}</h3><h3 /><h3>5. Factor the number : 45 = 3 × 15</h3>

<h3>=  \frac{3 \times 15}{3 \times 15 \times 2}</h3><h3 /><h3>6. Cancel the common factor : 3 </h3>

<h3>=  \frac{15}{15 \times 2}</h3>

<h3>7. Cancel the common factor : 15</h3>

<h3>=  \frac{1}{2}</h3><h2 /><h2>Solution : </h2>

<h2>= \frac{1}{2}</h2>
mixer [17]2 years ago
5 0

Answer:

[-4/5]×3/7×15/16×[-14/9]= 1/2

Step-by-step explanation:

hope this helps :)

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Answer:

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Step-by-step explanation:

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The correct factorization of 12x'2 - 157x - 40: A) (3x -8)(4x - 5) B) (3x - 40)(4x + 1) C) (12x - 1)(x + 40) D) (12x - 5)(x-8)​
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Answer:

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Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

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Use these factors to split the x- term

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= (4x + 1)(3x - 40) ← in factored form → B

8 0
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