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3 years ago

Give one example of when you would draw a diagram to solve an angle measurement problem

1 answer:

5 0

An example of an angle measurement problem is when trying to calculate for the height of a particular object given the distance of the observer from the object and the angle of elevation or depression. For example, you want to find out the height of a building. All you need to know is the distance of your point of origin to the building and the angle of elevation.

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X+y=5 x×y=6 Solve simultaneously with steps

igor_vitrenko [27]

Answer:

(3, 2), (2, 3)

Step-by-step explanation:

x + y = 5

xy = 6

Solve the first equation for x.

x = 5 - y

Substitute 5 - y for x in the second equation.

xy = 6

(5 - y)y = 6

5y - y² = 6

y² - 5y + 6 = 0

Factor.

(y - 2)(y - 3) = 0

y - 2 = 0 or y - 3 = 0

y = 2 or y = 3

Now substitute 2 for y in the first equation and solve for x.

x + y = 5

x + 2 = 5

x = 3

One solution is x = 3; y = 2, or (3, 2).

Now substitute 3 for y in the first equation and solve for x.

x + y = 5

x + 3 = 5

x = 2

Another solution is x = 2; y = 3, or (3, 2).

Answer: (3, 2), (2, 3)

7 0

1 year ago

What is the area, in square centimeters, of the trapezoid below? 18.2 cm 9.2 cm 8.3 cm

zubka84 [21]

Answer:
113.71 cm^2
Explanation m:
Area= a+b/2 h
18.2 + 9.2/2 •8.3 = 113.71

5 0

2 years ago

Divide: 28.324 : 0.4 A 0.7081 B 7,081 C 708.1 D 70.81

valina [46]

Answer:

D-70.81

Step-by-step explanation:

I did the math, this should be correct.

Good luck!

3 0

1 year ago

Read 2 more answers

Ok umm whoever this katie girl is she is making me real mad like fr she has deleted most of my answers because after i answer i

alisha [4.7K]

Yea it isss like omg

7 0

2 years ago

In a certain communications system, there is an average of 1 transmission error per 10 seconds. Assume that the distribution of

Nitella [24]

Answer:

The probability of 1 error in a period of 0ne - half minute is 0.1494

Step-by-step explanation:

Formula for poisson distribution:

$P (X = k) = \frac{\exp^{- \lambda} \lambda^{x} }{x!}$

If there is an average of 1 error in 10 seconds

In one-half minutes (i.e. 30 seconds), there will be an average of 30/10 errors = 3 errors

$\lambda = 3 errors\\x = 1$

$P (X = 1) = \frac{\exp^{-3} 3^{1} }{1!}$

1! = 1

$P (X = 1) = 3 \exp^{-3}$

P(X = 1) = 3 * 0.0498

P(X = 1) = 0.01494

7 0

3 years ago

Read 2 more answers