Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
Answer:
1. In the dispersive model, each strand of both daughter molecules contains a mixture of old and newly synthesized DNA, and in the semiconservative model, each new double helix consists of one old and one new strand.
Explanation: it helps to remember that dispersive means to disperse your DNA molecules! And semi conservative means you keep one of your old strands! Hope this helps!
A. Yes is correct.
Hope that helps!
Chesapeake bay is an area that has suffered from overharvesting and eutrophication. Eutrophication is an enrichment of water by nutrients salts that causes structural changes in the ecosystem such as increased formation of algae and aquatic plants, depletion of fish species among other effects. The greatest source of nitrogen and phosphorus in a Chesapeake bay is agriculture
