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vova2212 [387]
2 years ago
5

In the figure below, what is the value of xº?

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
7 0

Answer:

62 degree

Step-by-step explanation:

A triangle has 180 degree

180 - (43 + 75) = 62

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Harry had $32. He spent all the money on buying 3 notebooks for $x each and 4 packs of index cards for $y each. If Harry had bou
NikAS [45]
The answer is The student's conclusion is incorrect because the solution to the system of equations 3x + 4y = 32 and <span>5x + 5y = 50 is (8, 2)

Harry's money is $ 32

He said that he spent ALL of his money buying 3 Notebooksx and 4 cards y, so the equation that represent this is </span> 
3x + 4y = 32 .

He said that HE IS SHORT $18 if he wants to buy 5 notebook x and 5 cards y,
So the equation that represent this is
5x + 5y = 32 + (18)
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And (8,2) is the only one that fit in both equation/



8 0
3 years ago
PLEASE HELP ASAP
Monica [59]
Well its not trinomical or binomical so i would put my best on monomial or polynomial so maybe choose 1 or the other look at which u think makes more sence
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Identify the slope as a fraction y=2x+1
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The slope will be 2/1x (2 over 1)
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6 0
3 years ago
Miles plans on leasing a new car and has been researching options from different dealerships. For the particular model he wants,
irga5000 [103]

Answer:

y = 179x +1999

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Step-by-step explanation:

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monthly lease rate of awesome autos= $249

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total amount paid towards the lease after x months=y

Now creating a system of linear equations that describes the total amount, y, paid towards the lease after x months:

the slope intercept form of any linear function is given as y=mx +b

where m= slope  of function and b=y-intercept

In given case, slope m gives the monthly lease rate and y-intercept b gives the down payment.

So the equations for the two linear functions will be:

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Putting the values of m=179 and b=1999, we get

y = 179x +1999

awesome autos:

Putting the values of m=249 and b=0, we get

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3 0
3 years ago
Multiply 12x to the 4th (-5 over 6x to the 3rd y squared)
timofeeve [1]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}

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3 0
3 years ago
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