Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
Answer: $26
Step-by-step explanation:
If $19.50 is 3/4, we need to find 4/4.
3/4 -> 0.75
4/4 -> 1
We will set up a proportion and solve.
19.5 = 0.75x
26 = x
The professional ball is $26.
3). y = -1/3x + 5
4). y = -1x +5
Slope intercept form: y = mx + b
m = slope
b = y intercept
Answer:
6 dollars
Step-by-step explanation:
40-10=30
30/5= 6
