Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
18/60 which is equal to 3/10
So you just need to put it into proportions which is blue to total. The total is 60 and there is 18 blue. Then you only need to simplify.
Answer:
x = 9
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(24+3) * 3 = x^2
27*3 = x^2
81 = x^2
Take the square root of each side
sqrt(81) = sqrt(x^2)
9 =x
They are parallel to each other