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seropon [69]
4 years ago
8

20 POINTSSSS!!!!!!

Mathematics
1 answer:
tangare [24]4 years ago
3 0
Big cone:
1/3 * Pi * 6^2 * 16
= 192 Pi

small cone :
1/3 * Pi * 3^2 * 8
=24 Pi

Big cone - small cone:
=192 Pi - 24 Pi = 168 Pi
=168 Pi = 527.7875658

volume of small cone = 24 pi /75.39822368
volume of the frustrum = 168 Pi / 527.7875658
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Luke made an elaborate code to remember the 10-digit combination to his bicycle lock. This is the code he came up with: F-G-E-D-
otez555 [7]

Answer:

lalalalalalalalallalalalalalaalalalalalalalalallalaalalalalalalala

5 0
3 years ago
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A ball is thrown into the air at an initial velocity of 18 meters per second from an initial height of 10 meters. The equation t
Sergio039 [100]

Answer:

Step-by-step explanation:

This is your position equation:

s(t)=-4.9t^2+18t+10

There's a whole lot of information in that equation, but what we are concerned about right now is the height of the ball after t = 3 seconds.  If this is the position of the ball at any time t, we will sub in 3 for t to find out where the ball is at 3 seconds.

s(3)=-4.9(3^2)+18(3)+10

which simplifies to

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7 0
4 years ago
Could i get an explanation on how to do this?
irina [24]

Answer:

EH is 25

Step-by-step explanation:

7+7+11=25

EH is 25

8 0
3 years ago
Brian has a gift card with a $250 balance. He buys several video games that cost $33 each. After the purchases, his gift card ba
Jet001 [13]

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8 0
3 years ago
according to chebyshev's theorem, what perpent of the observatioons lie within plus and minus 2.5 standard deviations of the mea
Andrews [41]

percent of the observations lie within plus and minus 2.5 standard deviations of the mean is 84%

according to Chebyshev's theorem k=2.5

Chebyshev theorem:

The minimum percentage of observations that are within a given range of standard deviations from the mean is calculated using Chebyshev's Theorem. Numerous other probability distributions can be applied with this theorem. Chebyshev's Inequality is another name for Chebyshev's Theorem.

This indicates that 1 - \frac{1}{k^{2} } of the distribution will be close to the mean, or within k standard deviations.

Therefore, 1 - \frac{1}{k^{2} }

⇒ 1- \frac{1}{(2.5)^{2} }

⇒1-\frac{1}{6.25}

⇒\frac{5.25}{6.25}

⇒0.84

percent of the observations lie within plus and minus 2.5 standard deviations of the mean is 84%

Learn more about standard deviations here:

brainly.com/question/16555520

#SPJ4

8 0
2 years ago
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