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arsen [322]
3 years ago
13

Where do the equations y=2x and y=

{2} " align="absmiddle" class="latex-formula">-3 intersect
Mathematics
1 answer:
never [62]3 years ago
8 0
Set 2x=x²-3 to each other.
Subtract 2x from both sides and get the following

x²-3-2x

Rearranging the formula to make factoring easier, we get
x²-2x-3

Factor and you should get the following:
(x-3)(x+1)

set both equal to 0 and solve for x.

x-3=0⇒x=3
x+1=0⇒x=-1

Now plug both of these values back into one of your original equations to get your y-values. It does not matter which equation you plug your xs back into due to the fact they intersect at the same x, and thus will also intersect at the same y.

For times sake,
y=2x
plug in x=3 and get y=6
plug in x=-1 and get y=-2

Ergo, the equations y=2x and y=x²-3 intersect at
(3,6) and (-1,-2)
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Answer: y2-1/y-4y+4

if this helped please mark brainliest

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3 years ago
If triangle ABC is rotated 180 degrees, reflected over the y-axis, and reflected over the X-axis, where will point A' lie?
Bumek [7]
The first one (5,-4)
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3 years ago
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For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
Talja [164]

Answer:

1.16

Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

This implies that:

P(0<Z<z) = 0.3770

P(Z < z)-P(Z < 0) = 0.3770

P(Z < z) = 0.3770 + P(Z < 0)

From the standard normal tables , P(Z < 0)  =0.5

P(Z < z) = 0.3770 + 0.5

P(Z < z) =  0.877

SO to determine the value of z for which it is equal to 0.877, we look at the

table of standard normal distribution and locate the probability value of 0.8770. we advance to the  left until the first column is reached, we see that the value was 1.1.  similarly, we did the same in the  upward direction until the top row is reached, the value was 0.06.  The intersection of the row and column values gives the area to the two tail of z.   (i.e 1.1 + 0.06 =1.16)

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8 0
3 years ago
118 {121÷(11×11)-(-4)-(3-7)}​
Rama09 [41]

<u>Q</u><u>uest</u><u>ion</u><u>:</u>

To Simplify:

118 {121÷(11×11)-(-4)-(3-7)}

<u>Solu</u><u>tion</u>:

↠118 {121÷121+4-(-4)}

↠118 {1+4+4}

↠118 {5+4}

↠118{9}

↠118×9

↠1062

▬▬▬▬▬▬▬▬▬▬▬▬

The upper Solution is done by applying BODMAS

<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>

B→ Bracket

O→ Of

D→ Division

M→ Multiplication

A→ Addition

S→ Subtraction

5 0
2 years ago
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Divide: 4/15÷8/25. What is the answer?
dybincka [34]
4/15 = 0.267
8/25 = 0.32
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3 years ago
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