Answer:7/36
Step-by-step explanation:
Firstly, I would draw a table to visually see what the outcomes are. There are many methods but this is what i find to be the easiest so here it goes!!!
I hope the pic helps! If you have any questions feel free to ask!
The answer is A because 1/3 is same as 3,1 (&) the 6 is alone without the 0 cause zero is worth nothing
Answer:
B) -9
Step-by-step explanation:
31+2= 33 --> -33 + 49= --> 16
-5x-5= 25
16 -25 = -9
Answer: (110.22, 125.78)
Step-by-step explanation:
The confidence interval for the population mean is given by :-

Given : Sample size = 463


Significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 90% confidence interval for the population mean will be :-

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)
S1=$70/20gal=$3.50 per gallon
s2=$33.50/(50/4)gal=$2.68 per gallon
s3=$48.75/(15+8)gal=$2.12 per gallon
So supplier #3 has the best deal.