Answer:
-8
Step-by-step explanation:
f(x) = 3x + 1
f(-3) = 3(-3) + 1
F(-3)=-9+1
f(-3)= -8
Material=wall+2*side and material is 40 ft so:
40=w+2s
w=40-2s
Area=ws, using w from above we get:
A=(40-2s)s
A=40s-2s^2
dA/ds=40-4s and d2A/ds2=-4
Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum.
dA/ds=0 when 4s=40, s=10 ft
And since w=40-2s, w=20 ft
So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
∠3 and ∠4 are angles that must be supplementary.
The x coordinate of S will be 1/2 * 2a = a.
and since the half triangle is 30-60-90 the y coordinate will be sqrt3 a
so S is (a , sqrt3a)
The answer is 23 because you would substitute in the 4 for the X and multiply 5 times 4 = 20 then add 20 plus 3 and you get 23
