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2 years ago

How many times larger is 4 × 10^10 than 2 × 10^8?

Mathematics

2 answers:

fgiga [73]2 years ago

7 0

Answer:10

Step-by-step explanation:

ICE Princess25 [194]2 years ago

3 0

Answer:

just a few times larger

Step-by-step explanation:

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This is so confusing all of it makes no sense

Tom [10]

Answer:

D). $4\sqrt{2}$

Step-by-step explanation:

STEP 1a: Find the last angle of the triangle. ( which is angle A)

$A+90+45=180$

STEP 1b: Solve the equation for A by adding 90 and 45.

$A+135=180$

STEP 1c: Then Move all terms not containing A to the right side of the equation by subtracting 135 from both sides of the equation

$A=180-135$

STEP 1d: Subtract 135 from 180.

$A=45$

STEP 2a: Find side b next.

STEP 2b: The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.

$cos(A)=\frac{adj}{hyp}$

STEP 2c: Substitute the name of each side into the definition of the cosine function.

$cos(A)=\frac{b}{c}$

STEP 2d: Set up the equation to solve for the adjacent side, in this case b.

$b=c*cos(A)$

STEP 2e: Substitute the values of each variable into the formula for cosine.

$b=8*cos(45)$

STEP 2f: Cancel the common factor of 2.

$a=4\sqrt{2}$

HOPE THIS HELPS!

4 0

2 years ago

Read 2 more answers

Someone help me please

galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: $a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }$

Hence, ∛27 = $27^{(\frac{1}{3})}$

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

$\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}$

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the multiplicative inverse of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0

2 years ago

Read 2 more answers

What is greater: 1) 0.48 or 6/15th? 2) 0.75 or 7/8th? 3) 7.025 or 7 1/8ths?

fgiga [73]

1) 0.48 3 2) 7/8 3) 7 1/8

4 0

3 years ago

A square carpet of side length 9 feet is designed with one large shaded square and eight smaller, congruent shaded squares, as s

Pepsi [2]

Answer:

$3\sqrt{3} + 72$

Step-by-step explanation:

I attached an image to aid the understanding of the question.

Looking at the image, we see that the 8 shaded parts are congruent, as affirmed in the question as well. And we are told that T = 3, this implies that the area of the square with T as it's side is 9ft². Since all the 8 squares are congruenrt, it means each square has its area to be 9. Therefore, the total area of the 8 shaded squares will be:

$9 \times 8 = 72ft^{2}$

It remains the area of the shaded square with side S.

From the question, we have the following ratio:

$\frac{9}{S} = \frac{S}{T}[\tex]But[tex]\frac{9}{S} = \frac{S}{3}[\tex]Multiplying through by 3S we have27 = S² and this gives:[tex]S = \sqrt{27} = 3\sqrt{3}$

I did not add ± because length is always positive, so the case of negative is eliminated.

Now the areas of S is $3\sqrt{3}$

Therefore, the total area of the shaded squares is

$3\sqrt{3} + 72$

3 0

2 years ago

Can someone help me with this proof

maksim [4K]

Step-by-step explanation:

Given :

Given that lines a and b are parallel, angles 1 and 5 are congruent because they are corresponding angles, and angles 1 and 4 are congruent because they are vertical angles

To find : by which property are angles 4 and 5 congruent

Solution :

We know that if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.

Also, we know that if two things are equal to the same thing then they are equal to each other . In this case, we can say that if two angles are congruent to a third angle, then they are congruent to each other. As angles 4 and 5 are both congruent to angle 1, they are congruent to each other but angles 4 and 5 are alternate interior angles. So, if parallel lines have a transversal, alternate interior angles are congruent.

8 0

2 years ago