Answer:

Step-by-step explanation:
<u>Given Data:</u>
Base area =
= 108 in.²
Volume = V = 729 in.³
<u>Required:</u>
Height = h = ?
<u>Formula:</u>

<u>Solution:</u>
For h, rearranging formula:
![\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%20%3D%20%5Cfrac%7BV%7D%7BA_%7BB%7D%7D%20%5C%5C%5C%5Ch%20%3D%5Cfrac%7B729%20%5C%20in.%5E3%7D%7B108%20%5C%20in.%5E2%7D%20%5C%5C%5C%5Ch%20%3D%206.75%20%5C%20in.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:

Step-by-step explanation:
<u>Given:</u>

<u>Apply exponent rule of distribution:</u>

<u>Simplify the numerator:</u>

<u>Simplify the denominator:</u>

<u>Simplify:</u>

-> To explain this party since it is a bigger jump,
is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have
leftover too.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
$ 8,695.35
Step-by-step explanation:
This is a compound interest question
Amount after t years = A = P(1 + r/n)^nt
Where P = Initial Amount saved
r = interest rate
t = time in years
n = compounding frequency
A = 10,000
r = 3.5 %
t = 21 - 17 = 4 years
n = Compounded monthly = 12
Step 1
Converting R percent to r a decimal
r = R/100 = 3.5%/100 = 0.035 per year.
P = A / (1 + r/n)^nt
Solving our equation:
P = 10000 / ( 1 + (0.035/12)^12 ×4 =
P = $8,695.35
The principal investment required to get a total amount, principal plus interest, of $10,000.00 from interest compounded monthly at a rate of 3.5% per year for 4 years is $8,695.35.
Answer: i dont really know if im right but here! :L
Step-by-step explanation: Now, say G is an Abelian group, finitely generated from generator In this sense abelian groups are “more interesting” than vector spaces. and in the table below, the second last column is the identity, while the last column is cyclic of order 4, with 9g the generator
Answer:
So to graph using a table, the first step is...well... make a table. so you have a column of x and y. under the x column write down a bunch of values you would like to test. I am going to test -2 through 2.
x | y
-2|
-1|
0 |
1 |
2 |
Next, we have to plug each of those values into the equation y=2x to see what the corresponding y value is.
when x=-2 y=2(-2)=-4, when x=-1 y=2(-1)=-2, and so on...
x | y
-2|-4
-1|-2
0 |0
1 |2
2 |4
Next, graph those points on a coordinate plane. Each row on the table is a point on the graph, (x,y). Hope that helps!