-7 + 4(n-1). Use this and plug in 10 for n, making it
-7 + 4(9)
-7+36
29
<span>If f(x) = 2x + 3 and g(x) = (x - 3)/2,
what is the value of f[g(-5)]?
f[g(-5)] means substitute -5 for x in the right side of g(x),
simplify, then substitute what you get for x in the right
side of f(x), then simplify.
It's a "double substitution".
To find f[g(-5)], work it from the inside out.
In f[g(-5)], do only the inside part first.
In this case the inside part if the red part g(-5)
g(-5) means to substitute -5 for x in
g(x) = (x - 3)/2
So we take out the x's and we have
g( ) = ( - 3)/2
Now we put -5's where we took out the x's, and we now
have
g(-5) = (-5 - 3)/2
Then we simplify:
g(-5) = (-8)/2
g(-5) = -4
Now we have the g(-5)]
f[g(-5)]
means to substitute g(-5) for x in
f[x] = 2x + 3
So we take out the x's and we have
f[ ] = 2[ ] + 3
Now we put g(-5)'s where we took out the x's, and we
now have
f[g(-5)] = 2[g(-5)] + 3
But we have now found that g(-5) = -4, we can put
that in place of the g(-5)'s and we get
f[g(-5)] = f[-4]
But then
f(-4) means to substitute -4 for x in
f(x) = 2x + 3
so
f(-4) = 2(-4) + 3
then we simplify
f(-4) = -8 + 3
f(-4) = -5
So
f[g(-5)] = f(-4) = -5</span>
Answer:
Cosec <F = 73/55
Step-by-step explanation:
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
First you must know that;
Cosecant <F = 1/sin<F
Given
∠G=90°, GF = 48, EG = 55, and FE = 73.
ED ,= hyp = 73
EG = opp = 55*side facing <F
Using DOH CAH TOA
Sin theta = opp/hyp
Sin <F= 55/73
Reciprocate both sides
1/sinF = 73/55
Cosec <F = 73/55
Answer:
8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)
9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.
10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)
Step-by-step explanation:
For a couple of these, it is helpful to remember that (a-b) = -(b-a).
<h3>8d.</h3>
___
<h3>9b.</h3>
___
<h3>10b.</h3>
Neither solution makes any denominator be zero, so both are good solutions.
