1 in 100 or 1/100 would be the probability
Complete Question
The complete question is shown on the first uploaded image
Answer:
The 95% confidence interval is 
Step-by-step explanation:
From the question we are told that
The first sample size is 
The first proportion 
The second sample size is 
The second proportion is 
Given that the confidence level is 95% then the level of significance is mathematically represented as


From the normal distribution table we obtain the critical value of
the value is

Now using the formula from the question to construct the 95% confidence interval we have

Here 
=> 
=> 
and

=> 
=> 
So


8(t+2)-3(t-4) = 6(t-7)+8
8t+16-3t+12=6t-42+8
5t+28=6t-34
t = 62
Answer:
x = - 7, x = - 1
Step-by-step explanation:
To find the zeros let f(x) = 0 , that is
x² + 8x + 7 = 0
Consider the factors of the constant term (+ 7) which sum to give the coefficient of the x- term (+ 8)
The factors are + 7 and + 1 , since
7 × 1 = + 7 and 7 + 1 = + 8 , then
x² + 8x + 7 = 0
(x + 7)(x + 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 7 = 0 ⇒ x = - 7
x + 1 = 0 ⇒ x = - 1
I think the answer is A. 3.
B. no, to big a number
C. no, to small a number
D. no, again, too big a number.
Have a nice day and hope this helps!