Answer:
π
Step-by-step explanation:
Solve for x on the interval [0, 2pi]
Given the equation
Sinx = cosx + 1
Square both sides of the equation
Sin²x = (cos x + 1)²
Sin²x = cos²x + 2cos x + 1
Since Sin²x = 1 - cos²x
1 - cos²x = cos²x + 2cos x + 1
Collect like terms
1-1-cos²x-cos²x-2cos x = 0
-2cos²x-2cos x = 0
-2cos²x = 2cos x
-cosx = 1
cos x = -1
x = arccos -1
x = 180 degrees
<em>Hence the value of x = π</em>
Answer:
Top left one on the attached, must be option A
Step-by-step explanation:
A function has to have unique input values and for each input value has to have an output value.
Analyzing the graphs we can see that only one of them is a function- top left one
All the others have repeat input values, therefore are not functions
All those points marked with red circle
<em>Refer to attached </em>
Answer:
B is the answer
Step-by-step explanation:
fjshrnxjcnf s
Answer:
c
Step-by-step explanation:
Answer:
g = 0
Step-by-step explanation:
4 = 2(3g + 2) ← divide both sides by 2
2 = 3g + 2 ( subtract 2 from both sides )
0 = 3g , then
g = 0
