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zloy xaker [14]
3 years ago
5

Can some one please help me

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Basically, all you have to do is substitue the terms given at the top.

x = -3

y = 6

z = -4

<em>The first one will be set up like this:</em>

(-3) + 6 + (-1) = 2

<em>The second one will be set up like this: </em>

-15 + (- -3) + 6 = -6

<em>The third one will be set up like this:</em>

3(-3) - 2(6) + (-4) = -25

<em>The fourth one will be set up like this:</em>

2(-4) - 3 (6) + 4(-3) = -38

<em>The fifth one will be set up like this: </em>

3 ( -3) + 2 (6) + (-4) = -1

<em>The sixth will be set up like this: </em>

(-3)(-4)

---------- = -1

-2 (6)

<em>The seventh will be set up like this:</em>

2 (6) (-4) - 3 (-3) = -39

Hope this helps! Have a good day/night! c:

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Answer:

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Step-by-step explanation:

<h3>First let's write our equation</h3><h3 /><h3>\frac{6}{d-6} =\frac{4}{8}</h3><h3 /><h3>Reduce</h3>

<em>Definition -  </em><em>reduction refers to the rewriting of an expression into a simpler form</em>

<h3 />

We can reduce \frac{4}{8} to \frac{1}{2}

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Now we can cross multiply

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d-6=12

<h3>Add</h3>

We are adding because we want our variable to be on one side of the equation

d=18

<h3>To check we can show our equation but instead of d we have 18</h3><h3 />

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<h3><em>Have a good day!</em></h3>
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