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Allushta [10]
1 year ago
15

Determine the truth value of the statement if the domain for all variables is the set of nonnegative integers.

Mathematics
1 answer:
Nadya [2.5K]1 year ago
8 0

The domain for all variables of the set of nonnegative integers given is true.

<h3>How to explain the truth value?</h3>

From the information given, we are given ∃n∀m(m< n). This implies that for all m, there exists n such that m × n where m and n are non negative integers.

This statement is true because for any non negative integer, the least value is zero and the set is unbounded.

Learn more about integer on:

brainly.com/question/17695139

#SPJ1

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The length of a rectangle is 3 inches more than twice its width, and its area is 65 square inches. What is the width?
tino4ka555 [31]

That makes no sense, what DO you get?

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3 years ago
Lisa needs 250 yards of yarn to knit a hat. She has 185 yards of yarn and needs to buy the rest. How many yards of yarn does she
Alecsey [184]

Answer:

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6 0
3 years ago
What do I do for this problem
slamgirl [31]

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3 years ago
What factors do 16 and 24 have in common?
ycow [4]
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5 0
3 years ago
I don’t understand this help please
Elodia [21]

Answer:

  9

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

  <em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property

<em>   (a^b)^c = a^(b·c)</em>

This reduces your expression to ...

  (2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}

Now we can apply another two rules of exponents:

<em>   (a^b)(a^c) = a^(b+c)</em>

<em>   1/a^b = a^-b</em>

Using these, we have ...

  =2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9

The value of the expression is 9.

3 0
3 years ago
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