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3 years ago

What is the value of m if m/4 = 12

Mathematics

2 answers:

olga2289 [7]3 years ago

8 0

The answer is 48 because you have to multiply 4 to the other side, so 12 and you will get m= 48.

wolverine [178]3 years ago

3 0

Your answer is 48 because if you move 4 to 12 it would look like 12x4 and 12x4=48 and to check your work you will just do 48/4=12. Have an amazing day!

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30 is 120% of what number? show ur work

Yanka [14]

Answer:

30 is 120% of 25

Step-by-step explanation:

30 = 120% of y

$\frac{120}{100}$ × y = 30

After multiplying both sides by 100 and dividing both sides by 120, we have

y = 30 × $\frac{100}{120}$

y = 25

3 0

3 years ago

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Mamont248 [21]

Answer:

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Step-by-step explanation:

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3 years ago

For the given values of n and d, find integers q and r such that n = dq + r and 0 ≤ r < d. n = −67, d = 8

Firlakuza [10]

Answer:

$q = 8$

$r = 3$

Step-by-step explanation:

Given

$n = dq + r$

$0 \le r < d$

$n = 67$ --- not -67

$d = 8$

Required

Find q and r

Substitute values for d and b

$n = dq + r$

$67 = 8 * q + r$

$67 = 8q + r$

Make q the subject

$q = \frac{67 - r}{8}$

$0 \le r < d$ means that r is less than 8 but greater than or equal to 0

And r and q are integers.

Let $r = 3$

$q = \frac{67 - 3}{8}$

$q = \frac{64}{8}$

$q = 8$

No other true values of r and q can be gotten.

7 0

3 years ago

What is m∠C?<br><br><br><br> Enter your answer in the box.

suter [353]

The interior angles of a triangle add up to 180 degrees

3x + 2x + x = 180
6x = 180
x = 180/6
x = 30

< C = 2x.......2(30) = 60 <===
< B = 3x.......3(30) = 90
< A = x................. = 30

6 0

3 years ago

The sum of a 3 digit number and a 1 digit number is 217. The product of the numbers is 642. If one number is between 200 and 225

algol [13]

Let, the numbers be "x" and "y". Consider "x" as the triple digit number.
Now, according to the question,
x + y = 217..........................equation (1)

x * y = 642............................equation (2)

Now,
Taking equation (2),
x * y = 642
y = 642 / x..................................equation (3)

Now, Taking equation (1),
$x+y=217$

Substituting the value of y from equation (3), we get,

$x+ \frac{642}{x} =217$

$\frac{x *x+642}{x} =217$

$x^{2} +642 =217*x$

$x^{2} +642 =217x$

$x^{2} +642-217x =0$

$x^{2} -217x+642 =0$

$x^{2} -3x-214x+642 =0$

$x(x-3)-214(x-3)=0$

$(x-3)(x-214)=0$

Using zero product property,
EITHER,
x - 3 = 0
x = 3
OR,
x - 214 = 0
x = 214
Since, "x" is the triple digit number, x = 214.
Now,
Taking equation (2),
x * y = 642
Substituting the value of "x" in the equation, we get,
(214) * y = 642
y = 642 / 214
y = 3

So, the numbers are 214 and 3.

5 0

3 years ago