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Oksanka [162]
3 years ago
15

1) Solve the following system of equations algebraically. Give your solution as two

Mathematics
1 answer:
Bad White [126]3 years ago
8 0

For this case we have the following system of equations:

y = x ^ 2 + 7x + 12\\y = 2x + 8

Equating both equations we have:

x ^ 2 + 7x + 12 = 2x + 8\\x ^ 2 + 7x-2x + 12-8 = 0\\x ^ 2 + 5x + 4 = 0

We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:

4 + 1 = 5\\4 * 1 = 4

Then, the factorized equation is of the form:

(x + 4) (x + 1) = 0

Thus, the solutions are:

x_ {1} = - 4\\x_ {2} = - 1

We look for solutions for the variable "y":

y_ {1} = 2 (-4) + 8 = -8 + 8 = 0\\y_ {2} = 2 (-1) + 8 = -2 + 8 = 6

Thus, the system solutions are given by:(x_ {1}, y_ {1}): (- 4,0)\\(x_ {2}, y_ {2}): (- 1,6)

ANswer:

(x_ {1}, y_ {1}): (- 4,0)\\(x_ {2}, y_ {2}): (- 1,6)

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