We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
Answer:100 boys
Step-by-step explanation:
250 / 5 is 50.
50 x 2 is 100.
Answer:
0.4
Step-by-step explanation:
Let X be the random variable that represents the number of consecutive days in which the parking lot is occupied before it is unoccupied. Then the variable X is a geometric random variable with probability of success p = 2/3, with probability function f (x) = [(2/3)^x] (1/3)
Then the probability of finding him unoccupied after the nine days he has been found unoccupied is:
P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9). For a geometric aeatory variable:
P (X> = 10) = 1 - P (X <10) = 0.00002
P (X> = 9) = 1 - P (X <9) = 0.00005
Thus, P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9) = 0.00002 / 0.00005 = 0.4.
Answer:
probability of randomly selecting an employee who is female and under the age of 25= 0.15
In percentage= 15%
Step-by-step explanation:
There are 300 female employees. There are 80 employees who are under the age of 25
Probabilty of choosing a female employees= 300/400
Probabilty of choosing a female employees= 0.75
Probabilty of choosing an employees under the age of 25
= 80/400
Probabilty of choosing an employees under the age of 25
= 0.2
probability of randomly selecting an employee who is female and under the age of 25= 0.2*0.75
probability of randomly selecting an employee who is female and under the age of 25= 0.15
In percentage= 0.15*100
In percentage= 15%
Hey there!
When always adding or subtracting, you <em>always</em> have to <u>line up the decimal</u>.
When subtracting decimals with the same sign you <u>Line up the decimal</u>.
Hope this helps!
